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  2. Type conversion - Wikipedia

    en.wikipedia.org/wiki/Type_conversion

    Implicit type conversion, also known as coercion or type juggling, is an automatic type conversion by the compiler. Some programming languages allow compilers to provide coercion; others require it. In a mixed-type expression, data of one or more subtypes can be converted to a supertype as needed at runtime so that the program will run correctly.

  3. Boxing (computer programming) - Wikipedia

    en.wikipedia.org/wiki/Boxing_(computer_programming)

    However, the compiler automatically transforms the code so that the list will "silently" receive objects, while the source code only mentions primitive values. For example, the programmer can now write list. add (3) and think as if the int 3 were added to the list; but, the compiler will have actually transformed the line into list. add (new ...

  4. Strong and weak typing - Wikipedia

    en.wikipedia.org/wiki/Strong_and_weak_typing

    There are many examples of languages that allow implicit type conversions, but in a type-safe manner. For example, both C++ and C# allow programs to define operators to convert a value from one type to another with well-defined semantics. When a C++ compiler encounters such a conversion, it treats the operation just like a function call.

  5. Compatibility of C and C++ - Wikipedia

    en.wikipedia.org/wiki/Compatibility_of_C_and_C++

    C compilers do not name mangle symbols in the way that C++ compilers do. [20] Depending on the compiler and architecture, it also may be the case that calling conventions differ between the two languages. For these reasons, for C++ code to call a C function foo(), the C++ code must prototype foo() with extern "C".

  6. C Sharp syntax - Wikipedia

    en.wikipedia.org/wiki/C_Sharp_syntax

    The cast operator is not overloadable, but one can write a conversion operator method which lives in the target class. Conversion methods can define two varieties of operators, implicit and explicit conversion operators. The implicit operator will cast without specifying with the cast operator (()) and the explicit operator requires it to be used.

  7. Type inference - Wikipedia

    en.wikipedia.org/wiki/Type_inference

    It would be possible to infer the types of all the variables at compile time. In the example above, the compiler would infer that result and x have type integer since the constant 1 is type integer, and hence that add_one is a function int -> int. The variable result2 isn't used in a legal manner, so it wouldn't have a type.

  8. Most vexing parse - Wikipedia

    en.wikipedia.org/wiki/Most_vexing_parse

    [4] [5] Function types in C++ are usually hidden behind typedefs and typically have an explicit reference or pointer qualifier. To force the alternate interpretation, the typical technique is a different object creation or conversion syntax. In the type conversion example, there are two alternate syntaxes available for casts: the "C-style cast"

  9. C data types - Wikipedia

    en.wikipedia.org/wiki/C_data_types

    This behavior exists to avoid integer overflows in implicit narrowing conversions. For example, in the following code: For example, in the following code: In C23 , the boolean type was moved to bool , making the <stdbool.h> header now useless.