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Operator overloading is syntactic sugar, and is used because it allows programming using notation nearer to the target domain [1] and allows user-defined types a similar level of syntactic support as types built into a language. It is common, for example, in scientific computing, where it allows computing representations of mathematical objects ...
In the C language, the a[i] notation is syntactic sugar for *(a + i). [8] Likewise, the a->x notation is syntactic sugar for accessing members using the dereference operator (*a).x. The using statement in C# ensures that certain objects are disposed of correctly. The compiler expands the statement into a try-finally block. [9]
Operators that are in the same cell (there may be several rows of operators listed in a cell) are grouped with the same precedence, in the given direction. An operator's precedence is unaffected by overloading. The syntax of expressions in C and C++ is specified by a phrase structure grammar. [7] The table given here has been inferred from the ...
In languages that support operator overloading by the programmer (such as C++) but have a limited set of operators, operator overloading is often used to define customized uses for operators. In the example IF ORDER_DATE > "12/31/2011" AND ORDER_DATE < "01/01/2013" THEN CONTINUE ELSE STOP , the operators are: > (greater than), AND and < (less ...
Operator overloading works analogously to standard C++. Every * becomes a ^, every & becomes an %, but the rest of the syntax is unchanged, except for an important addition: for .NET classes, operator overloading is possible not only for classes themselves, but also for references to those classes.
The cast operator is not overloadable, but one can write a conversion operator method which lives in the target class. Conversion methods can define two varieties of operators, implicit and explicit conversion operators. The implicit operator will cast without specifying with the cast operator (()) and the explicit operator requires it to be used.
Often the compiler selects the overload to call based on the type of the input arguments or it fails if the input arguments do not select an overload. Older and weakly-typed languages generally do not support overloading. Here is an example of overloading in C++, two functions Area that accept different types:
Lisp definitively only has functions and not operators, much less operators with precedence and associativity. The justification that "operators use the same prefix syntax as functions" is a very feeble argument. With that argumentation every language supporting overloading of functions would also count as having operator overloading.