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Vacuum trajectory of a projectile for different launch angles. Launch speed is the same for all angles, 50 m/s, and "g" is 10 m/s 2. To hit a target at range x and altitude y when fired from (0,0) and with initial speed v the required angle(s) of launch θ are:
A launch angle of 45 degrees displaces the projectile the farthest horizontally. This is due to the nature of right triangles. Additionally, from the equation for the range :
Plot of trajectories of projectiles launched at different elevation angles but the same speed of 10 m/s in a vacuum and uniform downward gravity of 10 m/s^2; t = time from launch, T = time of flight, R = range and H = highest point of trajectory (indicated with arrows); points are at 0.05 s intervals and length of their tails is linearly ...
The minimum amount of cardio exercise you can get away with each week depends on your resting heart rate and your specific fitness goals, according to trainers. ... Air bike: Start with a 30 ...
A 2021 study found that the treadmill is the most effective cardio machine for weight loss. A trainer explains why—and reveals the best treadmill workouts.
To find the angle giving the maximum height for a given speed calculate the derivative of the maximum height = / with respect to , that is = / which is zero when = / =. So the maximum height H m a x = v 2 2 g {\displaystyle H_{\mathrm {max} }={v^{2} \over 2g}} is obtained when the projectile is fired straight up.
The test score is the time taken on the test, in minutes. This can also be converted to an estimated maximal oxygen uptake score using the calculator below and the following formulas, where the value "T" is the total time completed (expressed in minutes and fractions of a minute e.g. 9 minutes 15 seconds = 9.25 minutes). As with many exercise ...
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