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In computer programming, the act of swapping two variables refers to mutually exchanging the values of the variables. Usually, this is done with the data in memory. For example, in a program, two variables may be defined thus (in pseudocode): data_item x := 1 data_item y := 0 swap (x, y);
Using the XOR swap algorithm to exchange nibbles between variables without the use of temporary storage. In computer programming, the exclusive or swap (sometimes shortened to XOR swap) is an algorithm that uses the exclusive or bitwise operation to swap the values of two variables without using the temporary variable which is normally required.
A map of the 24 permutations and the 23 swaps used in Heap's algorithm permuting the four letters A (amber), B (blue), C (cyan) and D (dark red) Wheel diagram of all permutations of length = generated by Heap's algorithm, where each permutation is color-coded (1=blue, 2=green, 3=yellow, 4=red).
Re the example here, XOR is not the only way to swap two numbers, but it is just quite an easy one to understand since it only uses one operation. If the numbers to be swapped are in registers A,B and have initial values a,b the following also works: A <- A - B (A contains a-b) B <- B + A (B contains a) A <- B - A (A contains (a - (a-b) = b)
The reversal algorithm is the simplest to explain, using rotations. A rotation is an in-place reversal of array elements. This method swaps two elements of an array from outside in within a range. The rotation works for an even or odd number of array elements. The reversal algorithm uses three in-place rotations to accomplish an in-place block ...
Take an array of numbers "5 1 4 2 8", and sort the array from lowest number to greatest number using bubble sort. In each step, elements written in bold are being compared. Three passes will be required; First Pass ( 5 1 4 2 8 ) → ( 1 5 4 2 8 ), Here, algorithm compares the first two elements, and swaps since 5 > 1.
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The basic Fredkin gate [3] is a controlled swap gate (CSWAP gate) that maps three inputs (C, I 1, I 2) onto three outputs (C, O 1, O 2). The C input is mapped directly to the C output. If C = 0, no swap is performed; I 1 maps to O 1, and I 2 maps to O 2. Otherwise, the two outputs are swapped so that I 1 maps to O 2, and I 2 maps to O 1. It is ...