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2. What is short circuiting and how is it used when programming in...

   stackoverflow.com/questions/9344305

   Short-circuiting the evaluation of an expression means that only a part of the expression needs to be evaluated before finding its value. For example: a == null || a.size() == 0 If a is null, the a.size() == 0 subexpression won't be evaluated, because the boolean operator || evaluates to true if one of its operands is true. Similarly, for this ...

3. julia - Evaluation in definition - Stack Overflow

   stackoverflow.com/questions/50476921

   Is there a way to tell julia to evaluate test once in the definition of f? I expect that this is probably not going to be possible, in which case I have a slightly different question. If ar=[1,2,:x,-2,2*:x] is there any way to define f(x) to be the sum of ar, i.e. f(x) = 3*x+1?

4. Lazy evaluation in C++ - Stack Overflow

   stackoverflow.com/questions/414243

   This way, you can chain multiple operations (by providing appropriate overloads of course). The evaluation takes place only when the final result is assigned to a matrix instance. EDIT I should have been more explicit. As it is, the code makes no sense because although evaluation happens lazily, it still happens in the same expression.

5. Does JavaScript have "Short-circuit" evaluation? - Stack Overflow

   stackoverflow.com/questions/12554578

   In order to get the answer, we need to understand how the short-circuit evaluation works. By the MDN definition , the && operator in expr1 && expr2 performs as follows: Logical AND ( && ) evaluates operands from left to right, returning immediately with the value of the first falsy operand it encounters; if all values are truthy , the value of ...

6. Java- && Evaluation - Stack Overflow

   stackoverflow.com/questions/10195568

   1. && will be executed Left to right if any single condition false the condition will be break and Whole condition will be false. Suppose cond2 is false then cond3.. and others will not executed. In other hands If you use single & it will executed from left to right until all conditions processed doesn't matter false or true.

7. c# - Circular definition in a constant enum - Stack Overflow

   stackoverflow.com/questions/12729147

   Because the c# compiler intepretes the third ActivityStatus in: public const ActivityStatus ActivityStatus = ActivityStatus.Open; as the name of the constant being defined instead than the name of the enumeration - hence the circular reference: you are definining a constant in terms of the constant itself. In C# you can use the same name for ...

8. How can I have PHP avoid lazy evaluation? - Stack Overflow

   stackoverflow.com/questions/710919

   As such, there is some debate as to whether it is good practice to use this side effect to circumvent short-circuit evaluation. I would personally at least put a comment that the & is intentional, but if you want to be as pure as possible you should evaluate whether they are valid first and then do the if.

9. What are the rules for evaluation order in Java? - Stack Overflow

   stackoverflow.com/questions/6800590

   3) According to 15.7. Evaluation Order of JLS. The Java programming language guarantees that the operands of operators appear to be evaluated in a specific evaluation order, namely, from left to right. and. The left-hand operand of a binary operator appears to be fully evaluated before any part of the right-hand operand is evaluated. So:

10. call - javascript evaluation failed- karate - Stack Overflow

    stackoverflow.com/questions/61528107

    Watch the white space around the = sign. Normally if you use IDE support you can avoid these issues. You seem to have an extra space after pageNumber. So make this change: And param pageNumber = currentPage. I request you to please read the docs and examples. You are still un-necessarily making 2 calls. And over complicating your test.

11. Does Java have lazy evaluation? - Stack Overflow

    stackoverflow.com/questions/15189209

    In the absence of a static type system, the code would still fail. It is this lack of unification (static typing or not) that answers the question; no, Java does not have user-defined lazy evaluation. Of course, it can be emulated as above, but this is an uninteresting observation which follows from turing-equivalence.