Search results
Results from the WOW.Com Content Network
[1] Can one find a simple closed quasigeodesic on a convex polyhedron in polynomial time? [2] Can a simultaneous embedding with fixed edges for two given graphs be found in polynomial time? [3] Can the square-root sum problem be solved in polynomial time in the Turing machine model?
In Computers and Intractability [8]: 226 Garey and Johnson list the bin packing problem under the reference [SR1]. They define its decision variant as follows. Instance: Finite set of items, a size () + for each , a positive integer bin capacity , and a positive integer .
A Sudoku starts with some cells containing numbers (clues), and the goal is to solve the remaining cells. Proper Sudokus have one solution. [1] Players and investigators use a wide range of computer algorithms to solve Sudokus, study their properties, and make new puzzles, including Sudokus with interesting symmetries and other properties.
If B answers ja, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is indeed Random. Either way, C is not Random. If B answers da, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is not Random. Either way, you know the identity of a god who is ...
This examples uses three variables (A, B, C), and there are two possible assignments (True and False) for each of them. So one has 2 3 = 8 {\displaystyle 2^{3}=8} possibilities. In this small example, one can use brute-force search to try all possible assignments and check if they satisfy the formula.
An anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once. [1] For example, the word anagram itself can be rearranged into the phrase "nag a ram"; which is an Easter egg suggestion in Google after searching for the word "anagram". [2]
The sum of two biggest two-digit-numbers is 99+99=198. So O=1 and there is a carry in column 3. Since column 1 is on the right of all other columns, it is impossible for it to have a carry. Therefore 1+1=T, and T=2. As column 1 had been calculated in the last step, it is known that there isn't a carry in column 2.
For instance, for a word made of only two different letters, say n letters A and m letters B, the answer is, of course, 1 or 0 according to whether n = m or not, for the only way to form an anagram without fixed letters is to exchange all the A with B, which is possible if and only if n = m.