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In aqueous solution, sodium molybdate features dissociated sodium ions and tetrahedral molybdate (MoO 4 2-), which adopts a sulfate-like structure. The solid dihydrate material has a complex structure typical for alkali metal salts of oxyanions. The MoO 4 2-subunits are tetrahedral with Mo-O distances near 178 pm. [3] [9]
When the trap is triggered, the spring propels a dose of sodium cyanide into the animal's mouth, and the sodium cyanide combines with water in the mouth to produce poisonous cyanide gas. [2] In addition to the cyanide, the capsule contains a brightly-colored particle marker (orange in capsules used by the Wildlife Services , and yellow in ...
In chemistry, a molybdate is a compound containing an oxyanion with molybdenum in its highest oxidation state of +6: O − −Mo(=O) 2 −O −. Molybdenum can form a very large range of such oxyanions , which can be discrete structures or polymeric extended structures, although the latter are only found in the solid state.
Ammonium heptamolybdate is the inorganic compound whose chemical formula is (NH 4) 6 Mo 7 O 24, normally encountered as the tetrahydrate.A dihydrate is also known. It is a colorless solid, often referred to as ammonium paramolybdate or simply as ammonium molybdate, although "ammonium molybdate" can also refer to ammonium orthomolybdate, (NH 4) 2 MoO 4, and several other compounds.
The first heteropoly molybdate and first heteropolymetallate, yellow ammonium phosphomolybdate, (NH 4) 3 PMo 12 O 40 was discovered by Berzelius in 1826. [4] The phosphorus atom in the anion is termed the heteroatom, other heteroatoms are silicon and arsenic. The heteropoly-molybdenum blues have structures based on the Keggin structure.
Iron(II) molybdate is prepared by the reaction of iron(II) chloride or iron(II) sulfate [3] and sodium molybdate. Na 2 MoO 4 + FeSO 4 → Na 2 SO 4 + FeMoO 4.
Samarium(III) molybdate can be obtained by reacting samarium(III) nitrate and sodium molybdate in the pH range of 5.5~6.0. [2] Its single crystal can be grown at 1085 °C by the Czochralski method. [3] Samarium(III) molybdate can also be prepared by reacting samarium and molybdenum(VI) oxide:
It reacts with sodium molybdate at a high temperature to obtain NaNd(MoO 4) 2. [3] It reacts at roughly 350°C to 700°C with hydrogen sulfide to obtain neodymium sulfide and molybdenum disulfide. [4] At roughly 780K to 870K, it can be reduced by hydrogen to obtain Nd 2 Mo 3 O 9. [5]