Search results
Results from the WOW.Com Content Network
In physics and mechanics, torque is the rotational analogue of linear force. [1] It is also referred to as the moment of force (also abbreviated to moment). The symbol for torque is typically , the lowercase Greek letter tau. When being referred to as moment of force, it is commonly denoted by M.
The moment of force, or torque, is a first moment: =, or, more generally, .; Similarly, angular momentum is the 1st moment of momentum: =.Momentum itself is not a moment.; The electric dipole moment is also a 1st moment: = for two opposite point charges or () for a distributed charge with charge density ().
The newton-metre or newton-meter (also non-hyphenated, newton metre or newton meter; symbol N⋅m [1] or N m [1]) [a] is the unit of torque (also called moment) in the International System of Units (SI). One newton-metre is equal to the torque resulting from a force of one newton applied perpendicularly to the end of a moment arm that is one ...
often simply called moment or torque newton meter (N⋅m) mass: kilogram (kg) normal vector unit varies depending on context atomic number: unitless refractive index: unitless principal quantum number: unitless amount of substance: mole: power: watt (W) probability
Despite this, in practice torque units are commonly called the foot-pound (denoted as either lb-ft or ft-lb) or the inch-pound (denoted as in-lb). [4] [5] Practitioners depend on context and the hyphenated abbreviations to know that these refer to neither energy nor moment of mass (as the symbol ft-lb rather than lbf-ft would imply).
The equation for torque is very important in angular mechanics. Torque is rotational force and is determined by a cross product.This makes it a pseudovector. = where is torque, r is radius, and is a cross product.
However, the moment (torque) of a couple is independent of the reference point P: Any point will give the same moment. [1] In other words, a couple, unlike any more general moments, is a "free vector". (This fact is called Varignon's Second Moment Theorem.) [2]
Torque-free precessions are non-trivial solution for the situation where the torque on the right hand side is zero. When I is not constant in the external reference frame (i.e. the body is moving and its inertia tensor is not constantly diagonal) then I cannot be pulled through the derivative operator acting on L.