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Molecular orbital diagram of dioxygen. Oxygen has a similar setup to H 2, but now we consider 2s and 2p orbitals. When creating the molecular orbitals from the p orbitals, the three atomic orbitals split into three molecular orbitals, a singly degenerate σ and a doubly degenerate π orbital.
Molecular orbital diagram of two singlet excited states as well as the triplet ground state of molecular dioxygen. From left to right, the diagrams are for: 1 Δ g singlet oxygen (first excited state), 1 Σ + g singlet oxygen (second excited state), and 3 Σ − g triplet oxygen (ground state). The lowest energy 1s molecular orbitals are ...
The orbital wave functions are positive in the red regions and negative in the blue. The right column shows virtual MO's which are empty in the ground state, but may be occupied in excited states. In chemistry, a molecular orbital (/ ɒr b ə d l /) is a mathematical function describing the location and wave-like behavior of an electron in a ...
The dot-and-cross diagram for molecular oxygen in the ground state. The oxygen nuclei are as indicated and the electrons are denoted by either dots or crosses, depending on their relative spins. The above three-dimensional LDQ structures are useful for visualising the molecular structures, but they can be laborious to construct.
Date/Time Thumbnail Dimensions User Comment; current: 22:16, 7 January 2015: 430 × 648 (58 KB): Rjlanc: defining z as bond direction with x and y for pi orbitals
Chlorine and oxygen can bond in a number of ways: chlorine monoxide radical, ClO•, chlorine (II) oxide radical; chloroperoxyl radical, ClOO•, chlorine (II) peroxide radical; chlorine dioxide, ClO 2, chlorine (IV) oxide; chlorine trioxide radical, ClO 3 •, chlorine (VI) oxide radical; chlorine tetroxide radical, ClO 4 •, chlorine (VII ...
The highest occupied orbital energy level of dioxygen is a pair of antibonding π* orbitals. In the ground state of dioxygen, this energy level is occupied by two electrons of the same spin, as shown in the molecular orbital diagram. The molecule, therefore, has two unpaired electrons and is in a triplet state.
Count valence electrons. Nitrogen has 5 valence electrons; each oxygen has 6, for a total of (6 × 2) + 5 = 17. The ion has a charge of −1, which indicates an extra electron, so the total number of electrons is 18. Connect the atoms by single bonds. Each oxygen must be bonded to the nitrogen, which uses four electrons—two in each bond.