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  2. Wedge - Wikipedia

    en.wikipedia.org/wiki/Wedge

    The mechanical advantage or MA of a wedge can be calculated by dividing the height of the wedge by the wedge's width: [1] M A = L e n g t h W i d t h {\displaystyle {\rm {MA={Length \over Width}}}} The more acute , or narrow, the angle of a wedge, the greater the ratio of the length of its slope to its width, and thus the more mechanical ...

  3. Exterior algebra - Wikipedia

    en.wikipedia.org/wiki/Exterior_algebra

    The wedge product was introduced originally as an algebraic construction used in geometry to study areas, volumes, and their higher-dimensional analogues: The magnitude of a 2-blade is the area of the parallelogram defined by and , and, more generally, the magnitude of a -blade is the (hyper)volume of the parallelotope defined by the ...

  4. Area of a triangle - Wikipedia

    en.wikipedia.org/wiki/Area_of_a_triangle

    Furthermore, the choice of coordinate system defined by L commits to only two degrees of freedom rather than the usual three, since the weight is a local distance (e.g. x i+1 − x i in the above) whence the method does not require choosing an axis normal to L.

  5. Critical taper - Wikipedia

    en.wikipedia.org/wiki/Critical_taper

    The result of these feedbacks is the stable angle of the wedge known as the critical taper. When natural processes (such as erosion, or an increase in load on the wedge due to emplacement of a sea or ice cap) change the shape of the wedge, the wedge will react by internally deforming to return to a critically tapered wedge shape. The critical ...

  6. Differential form - Wikipedia

    en.wikipedia.org/wiki/Differential_form

    Alternating also implies that dx i ∧ dx i = 0, in the same way that the cross product of parallel vectors, whose magnitude is the area of the parallelogram spanned by those vectors, is zero. In higher dimensions, dx i 1 ∧ ⋅⋅⋅ ∧ dx i m = 0 if any two of the indices i 1 , ..., i m are equal, in the same way that the "volume" enclosed ...

  7. ‘1000-Lb Best Friends’ Star Vannessa Cross Reveals ... - AOL

    www.aol.com/lifestyle/1000-lb-best-friends-star...

    Over the past two years, 1000-Lb Best Friends star Vannessa Cross worked diligently to drop a staggering 200 pounds—and now she has revealed her staggering weight loss transformation. “My life ...

  8. Hodge star operator - Wikipedia

    en.wikipedia.org/wiki/Hodge_star_operator

    The Hodge star relates the exterior and cross product in three dimensions: [2] = =. Applied to three dimensions, the Hodge star provides an isomorphism between axial vectors and bivectors , so each axial vector a is associated with a bivector A and vice versa, that is: [ 2 ] A = ⋆ a , a = ⋆ A {\displaystyle \mathbf {A} ={\star }\mathbf {a ...

  9. “1000-Lb. Best Friends”’ Vannessa Cross Wants a ... - AOL

    www.aol.com/1000-lb-best-friends-vannessa...

    Cross added in the clip, “I have been maintaining my weight so [fingers crossed].” The season 3 premiere of 1,000-Lb. Best Friends airs Tuesday, October 22 at 10pm ET/PT on TLC and discovery+.