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It is a graphical plot of nE° = −ΔG°/F as a function of the oxidation number for the different redox species of a given element. The Gibbs free energy Δ G ° is related to the reduction potential E ° by the formula: Δ G ° = − nFE ° or nE ° = −Δ G °/ F , where n is the number of transferred electrons, and F is the Faraday ...
For example, in the above reaction, it can be shown that this is a redox reaction in which Fe is oxidised, and Cl is reduced. Note the transfer of electrons from Fe to Cl. Decomposition is also a way to simplify the balancing of a chemical equation. A chemist can atom balance and charge balance one piece of an equation at a time. For example:
For example, Cu compounds with Cu oxidation state +2 are call cupric and those with state +1 are cuprous. [4]: 172 The oxidation numbers of elements allow predictions of chemical formula and reactions, especially oxidation-reduction reactions. The oxidation numbers of the most stable chemical compounds follow trends in the periodic table.
In these cases the oxidation number (the same as the charge) of the metal ion is represented by a Roman numeral in parentheses immediately following the metal ion name. For example, in uranium(VI) fluoride the oxidation number of uranium is 6. Another example is the iron oxides. FeO is iron(II) oxide and Fe 2 O 3 is iron(III) oxide.
Element Negative states Positive states Group Notes −5 −4 −3 −2 −1 0 +1 +2 +3 +4 +5 +6 +7 +8 +9 Z; 1 hydrogen: H −1 +1: 1 2 helium: He 0 18
For example, if the manganese in [HMnO 4] − has an oxidation state of +6 and nE° = 4, and in MnO 2 the oxidation state is +4 and nE° = 0, then the slope Δy/Δx is 4/2 = 2, yielding a standard potential of +2. The stability of any terms can be similarly found by this graph.
In the above equation, the Iron (Fe) has an oxidation number of 0 before and 3+ after the reaction. For oxygen (O) the oxidation number began as 0 and decreased to 2−. These changes can be viewed as two "half-reactions" that occur concurrently: Oxidation half reaction: Fe 0 → Fe 3+ + 3e −; Reduction half reaction: O 2 + 4e − → 2 O 2−
The chlorine reactant is in oxidation state 0. In the products, the chlorine in the Cl − ion has an oxidation number of −1, having been reduced, whereas the oxidation number of the chlorine in the ClO − 3 ion is +5, indicating that it has been oxidized. Decomposition of numerous interhalogen compounds involve disproportionation.
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