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  2. Mathematical induction - Wikipedia

    en.wikipedia.org/wiki/Mathematical_induction

    Mathematical induction can be informally illustrated by reference to the sequential effect of falling dominoes. [1] [2]Mathematical induction is a method for proving that a statement () is true for every natural number, that is, that the infinitely many cases (), (), (), (), … all hold.

  3. All horses are the same color - Wikipedia

    en.wikipedia.org/wiki/All_horses_are_the_same_color

    The argument above makes the implicit assumption that the set of + horses has the size at least 3, [3] so that the two proper subsets of horses to which the induction assumption is applied would necessarily share a common element. This is not true at the first step of induction, i.e., when + =.

  4. Mathematical proof - Wikipedia

    en.wikipedia.org/wiki/Mathematical_proof

    In proof by mathematical induction, a single "base case" is proved, and an "induction rule" is proved that establishes that any arbitrary case implies the next case. Since in principle the induction rule can be applied repeatedly (starting from the proved base case), it follows that all (usually infinitely many) cases are provable. [ 15 ]

  5. Glossary of logic - Wikipedia

    en.wikipedia.org/wiki/Glossary_of_logic

    The initial case in a proof by mathematical induction. Bayes' theorem A theorem in probability theory used to update the probability for a hypothesis as more evidence or information becomes available. begging the question A logical fallacy where the conclusion of an argument is assumed in the premise, making the argument circular. Bew

  6. Chebyshev's sum inequality - Wikipedia

    en.wikipedia.org/wiki/Chebyshev's_sum_inequality

    Consider the sum = = = (). The two sequences are non-increasing, therefore a j − a k and b j − b k have the same sign for any j, k.Hence S ≥ 0.. Opening the brackets, we deduce:

  7. Bernoulli's inequality - Wikipedia

    en.wikipedia.org/wiki/Bernoulli's_inequality

    Bernoulli's inequality can be proved for case 2, in which is a non-negative integer and , using mathematical induction in the following form: we prove the inequality for {,}, from validity for some r we deduce validity for +.

  8. 2025 NFL mock draft: Expert projections for Cam Ward ... - AOL

    www.aol.com/2025-nfl-mock-draft-expert-192129777...

    The 2025 NFL draft order was shaken up by a Raiders win over the Jaguars in Week 16. Here's how that's impacting NFL mock drafts.

  9. Gagliardo–Nirenberg interpolation inequality - Wikipedia

    en.wikipedia.org/wiki/Gagliardo–Nirenberg...

    The core of the proof is based on two proofs by induction. Sketch of the proof of the Gagliardo-Nirenberg inequality [ 6 ] Throughout the proof, given j {\displaystyle j} and m {\displaystyle m} , we shall assume that θ = j m {\textstyle \theta ={\frac {j}{m}}} .