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  2. RSA (cryptosystem) - Wikipedia

    en.wikipedia.org/wiki/RSA_(cryptosystem)

    Breaking RSA encryption is known as the RSA problem. Whether it is as difficult as the factoring problem is an open question. [3] There are no published methods to defeat the system if a large enough key is used. RSA is a relatively slow algorithm. Because of this, it is not commonly used to directly encrypt user data.

  3. PKCS 1 - Wikipedia

    en.wikipedia.org/wiki/PKCS_1

    It provides the basic definitions of and recommendations for implementing the RSA algorithm for public-key cryptography. It defines the mathematical properties of public and private keys, primitive operations for encryption and signatures, secure cryptographic schemes, and related ASN.1 syntax representations. The current version is 2.2 (2012 ...

  4. RSA problem - Wikipedia

    en.wikipedia.org/wiki/RSA_problem

    More specifically, the RSA problem is to efficiently compute P given an RSA public key (N, e) and a ciphertext C ≡ P e (mod N). The structure of the RSA public key requires that N be a large semiprime (i.e., a product of two large prime numbers), that 2 < e < N, that e be coprime to φ(N), and that 0 ≤ C < N.

  5. RSA numbers - Wikipedia

    en.wikipedia.org/wiki/RSA_numbers

    The first RSA numbers generated, from RSA-100 to RSA-500, were labeled according to their number of decimal digits. Later, beginning with RSA-576, binary digits are counted instead. An exception to this is RSA-617, which was created before the change in the numbering scheme.

  6. RSA Factoring Challenge - Wikipedia

    en.wikipedia.org/wiki/RSA_Factoring_Challenge

    RSA Laboratories stated: "Now that the industry has a considerably more advanced understanding of the cryptanalytic strength of common symmetric-key and public-key algorithms, these challenges are no longer active." [6] When the challenge ended in 2007, only RSA-576 and RSA-640 had been factored from the 2001 challenge numbers. [7]

  7. Modular exponentiation - Wikipedia

    en.wikipedia.org/wiki/Modular_exponentiation

    Calculate c = (b ⋅ c) mod m; Output c; Note that at the end of every iteration through the loop, the equation c ≡ b e′ (mod m) holds true. The algorithm ends when the loop has been executed e times. At that point c contains the result of b e mod m. In summary, this algorithm increases e′ by one until it is equal to e.

  8. Elliptic-curve cryptography - Wikipedia

    en.wikipedia.org/wiki/Elliptic-curve_cryptography

    In comparison, using Shor's algorithm to break the RSA algorithm requires 4098 qubits and 5.2 trillion Toffoli gates for a 2048-bit RSA key, suggesting that ECC is an easier target for quantum computers than RSA. All of these figures vastly exceed any quantum computer that has ever been built, and estimates place the creation of such computers ...

  9. Blinding (cryptography) - Wikipedia

    en.wikipedia.org/wiki/Blinding_(cryptography)

    Blinding can also be used to prevent certain side-channel attacks on asymmetric encryption schemes. Side-channel attacks allow an adversary to recover information about the input to a cryptographic operation, by measuring something other than the algorithm's result, e.g., power consumption, computation time, or radio-frequency emanations by a ...