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Figure 1B: Low-pass filter (1st-order, one-pole) Bode magnitude plot (top) and Bode phase plot (bottom). The red data curve is approximated by the straight black line. In electrical engineering and control theory, a Bode plot is a graph of the frequency response of a system.
For a rational and continuous-time system, the condition for stability is that the region of convergence (ROC) of the Laplace transform includes the imaginary axis.When the system is causal, the ROC is the open region to the right of a vertical line whose abscissa is the real part of the "largest pole", or the pole that has the greatest real part of any pole in the system.
Bode's sensitivity integral, discovered by Hendrik Wade Bode, is a formula that quantifies some of the limitations in feedback control of linear parameter invariant systems. Let L be the loop transfer function and S be the sensitivity function .
The procedure outlined in the Bode plot article is followed. Figure 5 is the Bode gain plot for the two-pole amplifier in the range of frequencies up to the second pole position. The assumption behind Figure 5 is that the frequency f 0 dB lies between the lowest pole at f 1 = 1/(2πτ 1) and the second pole at f 2 = 1/(2πτ 2). As indicated in ...
A simple example of this is a pure time delay of time T, which has amplitude 1 at any frequency regardless of T, but has a phase dependent on T (specifically, phase = 2π × T × frequency). There is, however, a unique amplitude-vs-phase relation in the special case of a minimum phase system, [9] sometimes called the Bode gain–phase relation.
A complex number can be visually represented as a pair of numbers (a, b) forming a vector on a diagram called an Argand diagram, representing the complex plane. Re is the real axis, Im is the imaginary axis, and i is the "imaginary unit", that satisfies i 2 = −1.
As I understand the bode plot, is the transfer function as it is on the imaginary axis (s=jw). The question then is, why are poles or zeros on the real axis of the transfer function create corners and phase changes on the imaginary axis, at the same value of frequency as the pole or zero?
The final step depends on the geometry of the waveguide. The easiest geometry to solve is the rectangular waveguide. In that case, the remainder of the Laplacian can be evaluated to its characteristic equation by considering solutions of the form ψ ( x , y , z , t ) = ψ 0 e i ( ω t − k z z − k x x − k y y ) . {\displaystyle \psi (x,y,z ...
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related to: bode plot with imaginary poles definition geometry examples problemsThis site is a teacher's paradise! - The Bender Bunch