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  2. Gravity of Earth - Wikipedia

    en.wikipedia.org/wiki/Gravity_of_Earth

    So, to find the acceleration due to gravity at sea level, substitute the values of the gravitational constant, G, the Earth's mass (in kilograms), m 1, and the Earth's radius (in metres), r, to obtain the value of g: [20]

  3. Standard gravitational parameter - Wikipedia

    en.wikipedia.org/wiki/Standard_gravitational...

    The standard gravitational parameter μ of a celestial body is the product of the gravitational constant G and the mass M of that body. For two bodies, the parameter may be expressed as G ( m 1 + m 2 ) , or as GM when one body is much larger than the other: μ = G ( M + m ) ≈ G M . {\displaystyle \mu =G(M+m)\approx GM.}

  4. Gauss's law for gravity - Wikipedia

    en.wikipedia.org/wiki/Gauss's_law_for_gravity

    g is the gravitational field, G is the universal gravitational constant, and; M is the total mass enclosed within the surface ∂V. The left-hand side of this equation is called the flux of the gravitational field. Note that according to the law it is always negative (or zero), and never positive.

  5. Galaxy - Wikipedia

    en.wikipedia.org/wiki/Galaxy

    By comparison, the Earth's magnetic field has an average strength of about 0.3 G (Gauss) or 30 μT . Radio-faint galaxies like M 31 and M33, the Milky Way's neighbors, have weaker fields (about 5 μG), while gas-rich galaxies with high star-formation rates, like M 51, M 83 and NGC 6946, have 15 μG on average. In prominent spiral arms, the ...

  6. Gravitational binding energy - Wikipedia

    en.wikipedia.org/wiki/Gravitational_binding_energy

    For example, the fact that Earth is a gravitationally-bound sphere of its current size costs 2.494 21 × 10 15 kg of mass (roughly one fourth the mass of Phobos – see above for the same value in Joules), and if its atoms were sparse over an arbitrarily large volume the Earth would weigh its current mass plus 2.494 21 × 10 15 kg kilograms ...

  7. Outer space - Wikipedia

    en.wikipedia.org/wiki/Outer_space

    The energy required to reach Earth orbital velocity at an altitude of 600 km (370 mi) is about 36 MJ/kg, which is six times the energy needed merely to climb to the corresponding altitude. [93] The escape velocity required to pull free of Earth's gravitational field altogether and move into interplanetary space is about 11.2 km/s (25,100 mph).

  8. How astronomers used gravitational lensing to discover 44 new ...

    www.aol.com/news/astronomers-discovered-44-stars...

    The most powerful telescope to be launched into space has made history by detecting a record number of new stars in a distant galaxy. NASA's James Webb Space Telescope, history's largest and most ...

  9. Gravitational field - Wikipedia

    en.wikipedia.org/wiki/Gravitational_field

    Vector field (blue) and its associated scalar potential field (red). Point P between earth and moon is the point of equilibrium. In physics, a gravitational field or gravitational acceleration field is a vector field used to explain the influences that a body extends into the space around itself. [1]