enow.com Web Search

Search results

  1. Results from the WOW.Com Content Network
  2. Mathematical induction - Wikipedia

    en.wikipedia.org/wiki/Mathematical_induction

    Description. The simplest and most common form of mathematical induction infers that a statement involving a natural number n (that is, an integer n ≥ 0 or 1) holds for all values of n. The proof consists of two steps: The base case (or initial case): prove that the statement holds for 0, or 1. The induction step (or inductive step, or step ...

  3. Proof by exhaustion - Wikipedia

    en.wikipedia.org/wiki/Proof_by_exhaustion

    Proof by exhaustion, also known as proof by cases, proof by case analysis, complete induction or the brute force method, is a method of mathematical proof in which the statement to be proved is split into a finite number of cases or sets of equivalent cases, and where each type of case is checked to see if the proposition in question holds. [1]

  4. Mathematical proof - Wikipedia

    en.wikipedia.org/wiki/Mathematical_proof

    Then P(n) is true for all natural numbers n. For example, we can prove by induction that all positive integers of the form 2n − 1 are odd. Let P(n) represent " 2n − 1 is odd": (i) For n = 1, 2n − 1 = 2 (1) − 1 = 1, and 1 is odd, since it leaves a remainder of 1 when divided by 2. Thus P(1) is true.

  5. Structural induction - Wikipedia

    en.wikipedia.org/wiki/Structural_induction

    Structural induction is used to prove that some proposition P(x) holds for all x of some sort of recursively defined structure, such as formulas, lists, or trees. A well-founded partial order is defined on the structures ("subformula" for formulas, "sublist" for lists, and "subtree" for trees). The structural induction proof is a proof that the ...

  6. Bertrand's ballot theorem - Wikipedia

    en.wikipedia.org/wiki/Bertrand's_ballot_theorem

    Clearly the theorem is true if p > 0 and q = 0 when the probability is 1, given that the first candidate receives all the votes; it is also true when p = q > 0 as we have just seen. Assume it is true both when p = a − 1 and q = b, and when p = a and q = b − 1, with a > b > 0. (We don't need to consider the case. a = b {\displaystyle a=b}

  7. All horses are the same color - Wikipedia

    en.wikipedia.org/wiki/All_horses_are_the_same_color

    The argument above makes the implicit assumption that the set of + horses has the size at least 3, [3] so that the two proper subsets of horses to which the induction assumption is applied would necessarily share a common element. This is not true at the first step of induction, i.e., when + =.

  8. Transfinite induction - Wikipedia

    en.wikipedia.org/wiki/Transfinite_induction

    Transfinite induction requires proving a base case (used for 0), a successor case (used for those ordinals which have a predecessor), and a limit case (used for ordinals which don't have a predecessor). Transfinite induction is an extension of mathematical induction to well-ordered sets, for example to sets of ordinal numbers or cardinal ...

  9. Hilbert's basis theorem - Wikipedia

    en.wikipedia.org/wiki/Hilbert's_basis_theorem

    Hilbert's proof is highly non-constructive: it proceeds by induction on the number of variables, and, at each induction step use the non-constructive proof for one variable less. Introduced more eighty years later, Gröbner bases allow a direct proof that is as constructive as possible: Gröbner bases produce an algorithm for testing whether a ...