enow.com Web Search

Search results

  1. Results from the WOW.Com Content Network
  2. Factorization of polynomials - Wikipedia

    en.wikipedia.org/wiki/Factorization_of_polynomials

    A simplified version of the LLL factorization algorithm is as follows: calculate a complex (or p-adic) root α of the polynomial () to high precision, then use the Lenstra–Lenstra–Lovász lattice basis reduction algorithm to find an approximate linear relation between 1, α, α 2, α 3, . . . with integer coefficients, which might be an ...

  3. Fermat's factorization method - Wikipedia

    en.wikipedia.org/wiki/Fermat's_factorization_method

    Suppose N has more than two prime factors. That procedure first finds the factorization with the least values of a and b . That is, a + b {\displaystyle a+b} is the smallest factor ≥ the square-root of N , and so a − b = N / ( a + b ) {\displaystyle a-b=N/(a+b)} is the largest factor ≤ root- N .

  4. Pollard's p − 1 algorithm - Wikipedia

    en.wikipedia.org/wiki/Pollard%27s_p_%E2%88%92_1...

    Pollard's p − 1 algorithm is a number theoretic integer factorization algorithm, invented by John Pollard in 1974. It is a special-purpose algorithm, meaning that it is only suitable for integers with specific types of factors; it is the simplest example of an algebraic-group factorisation algorithm .

  5. Factorization - Wikipedia

    en.wikipedia.org/wiki/Factorization

    Start with division by 2: the number is even, and n = 2 · 693. Continue with 693, and 2 as a first divisor candidate. 693 is odd (2 is not a divisor), but is a multiple of 3: one has 693 = 3 · 231 and n = 2 · 3 · 231. Continue with 231, and 3 as a first divisor candidate. 231 is also a multiple of 3: one has 231 = 3 · 77, and thus n = 2 ...

  6. Lenstra elliptic-curve factorization - Wikipedia

    en.wikipedia.org/wiki/Lenstra_elliptic-curve...

    Let's choose the elliptic curve y 2 = x 3 + 5x – 5, with the point P = (1, 1) on it, and let's try to compute (10!)P. The slope of the tangent line at some point A=(x, y) is s = (3x 2 + 5)/(2y) (mod n). Using s we can compute 2A. If the value of s is of the form a/b where b > 1 and gcd(a,b) = 1, we have to find the modular inverse of b.

  7. Integer factorization - Wikipedia

    en.wikipedia.org/wiki/Integer_factorization

    To factorize a small integer n using mental or pen-and-paper arithmetic, the simplest method is trial division: checking if the number is divisible by prime numbers 2, 3, 5, and so on, up to the square root of n. For larger numbers, especially when using a computer, various more sophisticated factorization algorithms are more efficient.

  8. General number field sieve - Wikipedia

    en.wikipedia.org/wiki/General_number_field_sieve

    When using such algorithms to factor a large number n, it is necessary to search for smooth numbers (i.e. numbers with small prime factors) of order n 1/2. The size of these values is exponential in the size of n (see below). The general number field sieve, on the other hand, manages to search for smooth numbers that are subexponential in the ...

  9. Factorization of polynomials over finite fields - Wikipedia

    en.wikipedia.org/wiki/Factorization_of...

    For more factorization algorithms see e.g. Knuth's book The Art of Computer Programming volume 2. Algorithm Cantor–Zassenhaus algorithm. Input: A finite field F q of odd order q. A monic square free polynomial f in F q [x] of degree n = rd, which has r ≥ 2 irreducible factors each of degree d Output: The set of monic irreducible factors of f.

  1. Related searches c++ program factorial of a given number algorithm with two terms and 3 factors

    factorization of all integersfactorization formula
    factorization of all numberswhat is a factorization
    factorization theorem wiki