Search results
Results from the WOW.Com Content Network
The Tybee Island mid-air collision was an incident on February 5, 1958, in which the United States Air Force lost a 7,600-pound (3,400 kg) Mark 15 nuclear bomb in the waters off Tybee Island near Savannah, Georgia, United States. During a night practice exercise, an F-86 fighter plane collided with the B-47 bomber carrying the large weapon.
It is the location of a hydrogen bomb lost by a B-47 Stratojet bomber in 1958. This lost hydrogen bomb is also known as the Tybee Bomb.On the night of February 5, 1958, a B-47 Stratojet bomber carrying a hydrogen bomb on a night training flight off the Georgia coast collided with an F-86 Saberjet fighter at 36,000 feet.
The USAF claimed the B-47 tried landing at Hunter Air Force Base, Georgia three times before the bomb was jettisoned at 7,200 ft (2,200 m) near Tybee Island, Georgia. The B-47 pilot successfully landed in one attempt only after he first jettisoned the bomb.
The Tybee Island Police Department announced that they have found the body of the teenager who went missing Friday morning, according to a press release.
A worker places a section of metal barricade along a main road on Tybee Island, Ga., on Tuesday, April 16, 2024, a few days ahead of the weekend beach party known as Orange Crush.
For premium support please call: 800-290-4726 more ways to reach us
The original description page was Tybee Island mid-air collision-article.oga here. All following user names refer to en.wikipedia. All following user names refer to en.wikipedia. 2012-04-25 14:55 S Whistler 0×0× (5602023 bytes) {{Spoken article entry |title= 1958 Tybee Island mid-air collision |time= 4:42 |user_name= S_Whistler |date= 2012-04 ...
Main page; Contents; Current events; Random article; About Wikipedia; Contact us; Donate; Pages for logged out editors learn more