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The easiest way is to call strlen(). Seriously. It's already optimized by your compiler and/or library vendors, to be as fast as possible for your architecture. One common optimization is to remove the need to increase a counter, and compute the length from the pointer: size_t my_strlen(const char *s) {.
The code below does not print anything - int main() { char *input = "This is a string"; find_length(input); return 0; } void find_length(char *input){ printf("%s", ...
printf( "string length: %d\n", count ); Explanation: %*s will parse a string (up to the first whitespace characters) but will not store it because of the *. Then %n will store the numbers of characters consumed (which is the length of the string parsed) into count. Please note that %n is not necessarily counted for the return value of scanf():
60. Use strlen to find the length of (number of characters in) a string. const char *ptr = "stackoverflow"; size_t length = strlen(ptr); Another minor point, note that ptr is a string literal (a pointer to const memory which cannot be modified). Its better practice to declare it as const to show this.
If you do not have an upper bound for the length of file, you need to allocate the necessary amount of memory by using malloc(). – Erich Kitzmueller Commented Nov 13, 2014 at 13:58
If I don't know how long the word is, I cannot write char m[6];, The length of the word is maybe ten or twenty long. How can I use scanf to get input from the keyboard? #include <stdio.h> int...
Use strlen to get the length of a null-terminated string. sizeof returns the length of the array not the string. If it's a pointer (char *s), not an array (char s[]), it won't work, since it will return the size of the pointer (usually 4 bytes on 32-bit systems).
The simple method to find the number of objects in an array is to take the size of the array divided by the size of one of its elements. Use the sizeof operator which returns the object's size in bytes. // For size_t. #include <stddef.h>. char* names[] = { "A", "B", "C" };
If by size you mean how many characters, then Length is the property you are looking for. "".Length // 0. "1".Length // 1. "12".Length // 2. If by size you mean how many bytes then this is dependant on encoding and you can use the answer Snake Eyes has given. Encoding.Unicode.GetByteCount("") // 0.
Remember: A string in C is an array of chars which ends in character '\0'. Providing enough memory is reserved (the whole string + 1 byte fits on the array), the length of the string will be the number of bytes from the pointer (mystring[0]) to the character before '\0'