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{{convert|123|cuyd|m3+board feet}} → 123 cubic yards (94 m 3; 40,000 board feet) The following converts a pressure to four output units. The precision is 1 (1 decimal place), and units are abbreviated and linked.
In either case the full quartic can then be divided by the factor (x − 1) or (x + 1) respectively yielding a new cubic polynomial, which can be solved to find the quartic's other roots. If a 1 = a 0 k , {\displaystyle \ a_{1}=a_{0}k\ ,} a 2 = 0 {\displaystyle \ a_{2}=0\ } and a 4 = a 3 k , {\displaystyle \ a_{4}=a_{3}k\ ,} then x = − k ...
kilogram-force per square millimetre: kgf/mm 2: ≡ 1 kgf/mm 2 = 9.806 65 × 10 6 Pa [33] kip per square inch: ksi ≡ 1 kipf/sq in ≈ 6.894 757 × 10 6 Pa [33] long ton per square foot: ≡ 1 long ton × g 0 / 1 sq ft ≈ 1.072 517 801 1595 × 10 5 Pa: micrometre of mercury: μmHg ≡ 13 595.1 kg/m 3 × 1 μm × g 0 ≈ 0.001 torr ≈ 0.133 ...
the relationship between square feet and square inches is 1 square foot = 144 square inches, where 144 = 12 2 = 12 × 12. Similarly: 1 square yard = 9 square feet; 1 square mile = 3,097,600 square yards = 27,878,400 square feet; In addition, conversion factors include: 1 square inch = 6.4516 square centimetres; 1 square foot = 0.092 903 04 ...
The factor–label method can convert only unit quantities for which the units are in a linear relationship intersecting at 0 (ratio scale in Stevens's typology). Most conversions fit this paradigm. An example for which it cannot be used is the conversion between the Celsius scale and the Kelvin scale (or the Fahrenheit scale). Between degrees ...
If a quartic polynomial P(x) is reducible in k[x], then it is the product of two quadratic polynomials or the product of a linear polynomial by a cubic polynomial. This second possibility occurs if and only if P(x) has a root in k.
A typical use of this is the completing the square method for getting the quadratic formula. Another example is the factorization of x 4 + 1. {\displaystyle x^{4}+1.} If one introduces the non-real square root of –1 , commonly denoted i , then one has a difference of squares x 4 + 1 = ( x 2 + i ) ( x 2 − i ) . {\displaystyle x^{4}+1=(x^{2 ...
If this number is −q, then the choice of the square roots was a good one (again, by Vieta's formulas); otherwise, the roots of the polynomial will be −r 1, −r 2, −r 3, and −r 4, which are the numbers obtained if one of the square roots is replaced by the symmetric one (or, what amounts to the same thing, if each of the three square ...