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The idea becomes clearer by considering the general series 1 − 2x + 3x 2 − 4x 3 + 5x 4 − 6x 5 + &c. that arises while expanding the expression 1 ⁄ (1+x) 2, which this series is indeed equal to after we set x = 1.
The Cauchy convergence test is a method used to test infinite series for convergence. It relies on bounding sums of terms in the series. It relies on bounding sums of terms in the series. This convergence criterion is named after Augustin-Louis Cauchy who published it in his textbook Cours d'Analyse 1821.
The geometric series 1 / 2 − 1 / 4 + 1 / 8 − 1 / 16 + ⋯ sums to 1 / 3 .. The alternating harmonic series has a finite sum but the harmonic series does not.
If r < 1, then the series converges absolutely. If r > 1, then the series diverges. If r = 1, the root test is inconclusive, and the series may converge or diverge. The root test is stronger than the ratio test: whenever the ratio test determines the convergence or divergence of an infinite series, the root test does too, but not conversely. [1]
In mathematics, the comparison test, sometimes called the direct comparison test to distinguish it from similar related tests (especially the limit comparison test), provides a way of deducing whether an infinite series or an improper integral converges or diverges by comparing the series or integral to one whose convergence properties are known.
Now, note that a 1 − a 2 is a lower bound of the monotonically decreasing sequence S 2m+1, the monotone convergence theorem then implies that this sequence converges as m approaches infinity. Similarly, the sequence of even partial sum converges too.
If r = 1, the ratio test is inconclusive, and the series may converge or diverge. Root test or nth root test. Suppose that the terms of the sequence in question are non-negative. Define r as follows: = | |, where "lim sup" denotes the limit superior (possibly ∞; if the limit exists it is the same value). If r < 1, then the series
The test can be useful for series where n appears as in a denominator in f. For the most basic example of this sort, the harmonic series ∑ n = 1 ∞ 1 / n {\textstyle \sum _{n=1}^{\infty }1/n} is transformed into the series ∑ 1 {\textstyle \sum 1} , which clearly diverges.
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