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A skier, moving at 8m/s, slides to a stop on a level surface while moving 64m. Assuming her mass to be 60kg, what is the coefficient of friction between her skies and the snow?
Friction is (at a first approximation) a pressure tangential to the surface of contact between two bodies, directed against the movement, and proportional to the contact pressure, by the coefficient of friction μ μ. Thus totally it is equal to μmg μ m g, and will exert a deceleration equal to μg μ g. The law of accelerated motion gives v1 ...
I'm trying to work a physics problem about how to find the coefficient of static friction between two objects when given the initial velocity and distance. Specifically, the problem I am working is as follows: A crate is carried in a pickup truck traveling horizontally at 14.2 m/s.
I'm trying to work out a question where I need to calculate the coefficient of friction given the radius of the corner, the angle of the bank and the speed at which the corner can be taken. Specifically the question says . A speedway has banked turns of 31° and a radius of 304.8 m.
1. Let the x x axis be along the road, downwards and let the y y axis be perpendicular to the road upwards. Projection of gravitational acceleration on the x-axis is g sinθ g sin θ and −g cosθ − g cos θ on the y-axis. Friction is along the negative x x axis and is Fxf = −γvx F x f = − γ v x. Newton along x x is.
You are running on an icy sidewalk. Suddenly, you stop running and let yourself slide. You slide at an initial speed of 10 m/s. You slide for a distance of 16 meters and your final speed, when you stop sliding, is 7 m/s. With a mass of 60 kilograms, what is the force of kinetic friction of the ice? Any help is appreciated. Thanks
Q.) A car rounds a turn of radius 120 m on a flat road. If the coefficient of friction between the tires and the road is 0.50, what is the maximum speed of the car without skidding? I really don't get this problem. I get that centripetal force= mass* (velocity^2/radius) and frictional force = coefficient of friction*Normal force.
a = −5 3ms−2 a = − 5 3 m s − 2. Then find the force. F = ma = (12)(−5 3) = −20N F = m a = (12) (− 5 3) = − 20 N. Note that it is negative because it is decelerative. As they asked only for the magnitude, you can quote the final answer without the negative sign as 20N 20 N. ΔK = F. d Δ K = F. d or 1 2mv2 − 1 2mv20 = F ⋅ d 1 ...
Finding the coefficient of friction when a body is being pulled at an angle. 0.
1. A skier starts from rest at the top of a hill that is inclined at 10.5 10.5 degrees with the horizontal. The hillside is 200 200 m long, and the coefficient of friction between the snow and the skis is 0.075 0.075. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier move along the ...