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  2. Fourier–Motzkin elimination - Wikipedia

    en.wikipedia.org/wiki/Fourier–Motzkin_elimination

    Since all the inequalities are in the same form (all less-than or all greater-than), we can examine the coefficient signs for each variable. Eliminating x would yield 2*2 = 4 inequalities on the remaining variables, and so would eliminating y. Eliminating z would yield only 3*1 = 3 inequalities so we use that instead.

  3. Inequality (mathematics) - Wikipedia

    en.wikipedia.org/wiki/Inequality_(mathematics)

    Instead, the inequalities must be solved independently, yielding x < ⁠ 1 / 2 ⁠ and x ≥ −1 respectively, which can be combined into the final solution −1 ≤ x < ⁠ 1 / 2 ⁠. Occasionally, chained notation is used with inequalities in different directions, in which case the meaning is the logical conjunction of the inequalities ...

  4. Maclaurin's inequality - Wikipedia

    en.wikipedia.org/wiki/Maclaurin's_inequality

    Maclaurin's inequality is the following chain of inequalities: with equality if and only if all the are equal. For n = 2 {\displaystyle n=2} , this gives the usual inequality of arithmetic and geometric means of two non-negative numbers.

  5. Farey sequence - Wikipedia

    en.wikipedia.org/wiki/Farey_sequence

    Thus the first term to appear between ⁠ 1 / 3 ⁠ and ⁠ 2 / 5 ⁠ is ⁠ 3 / 8 ⁠, which appears in F 8. The total number of Farey neighbour pairs in F n is 2| F n | − 3. The Stern–Brocot tree is a data structure showing how the sequence is built up from 0 (= ⁠ 0 / 1 ⁠) and 1 (= ⁠ 1 / 1 ⁠), by taking successive mediants.

  6. Bernoulli's inequality - Wikipedia

    en.wikipedia.org/wiki/Bernoulli's_inequality

    Bernoulli's inequality can be proved for case 2, in which is a non-negative integer and , using mathematical induction in the following form: we prove the inequality for r ∈ { 0 , 1 } {\displaystyle r\in \{0,1\}} ,

  7. List of inequalities - Wikipedia

    en.wikipedia.org/wiki/List_of_inequalities

    Khabibullin's conjecture on integral inequalities; Kantorovich inequality; Karamata's inequality; Korn's inequality; Ladyzhenskaya's inequality; Landau–Kolmogorov inequality; Lebedev–Milin inequality; Lieb–Thirring inequality; Littlewood's 4/3 inequality; Markov brothers' inequality; Mashreghi–Ransford inequality; Max–min inequality ...

  8. Farkas' lemma - Wikipedia

    en.wikipedia.org/wiki/Farkas'_lemma

    There exist y 1, y 2 such that 6y 1 + 3y 2 ≥ 0, 4y 1 ≥ 0, and b 1 y 1 + b 2 y 2 < 0. Here is a proof of the lemma in this special case: If b 2 ≥ 0 and b 1 − 2b 2 ≥ 0, then option 1 is true, since the solution of the linear equations is = and =.

  9. Grönwall's inequality - Wikipedia

    en.wikipedia.org/wiki/Grönwall's_inequality

    In mathematics, Grönwall's inequality (also called Grönwall's lemma or the Grönwall–Bellman inequality) allows one to bound a function that is known to satisfy a certain differential or integral inequality by the solution of the corresponding differential or integral equation.