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The full signature for beta.rvs is: rvs(a, b, loc=0, scale=1, size=1, random_state=None) When I first wrote that this method produces a single value of a pseudorandom variable, I should have indicated that this would be by default, since size=1. That is, the method produces a sample of size one by default. The method is obviously capable of ...
rvs(loc=0, scale=1, size=1, random_state=None) If you look at the code (line 2771) you have: loc : array_like, optional Location parameter (default=0). size : int or tuple of ints, optional Defining number of random variates (Default is 1). Note that size has to be given as keyword, not as positional argument.
The advantage of this method over assigning it to the random_state of rv_continuous or rv_discrete is, that you always have explicit control over the random state of your rvs, whereas with my_dist.random_state = np.random.RandomState(seed=342423) the seed is lost after each call to rvs, possibly resulting in non-reproducible results when losing ...
This answer provided a brief introduction on scipy.stats.norm.rv.. To seed this function, I did the following and got the following results.
Here is a jupyter timing example: This, on my run with numpy version 1.11.1 and scipy 0.17.0, outputs: So just generating one random sample from rvs was almost 100x slower than using numpy directly. However, if you are generating an array of values than the gap closes (115 to 61.9 microseconds).
Is there a way to force .rvs to output only positive values? I thought of some ways but they seem pretty CPU intensive like making way more values than I would need and then doing a boolean mask for all the values that are positive and np.random.choice from those.
from scipy import stats. stats.norm.rvs(size=10) will give you a vector filled with 10 standard normal variates. note that multivariate means something specific in statistics, not just IID copies of the same (which is what size does). e.g. the cov parameter to multivariate_normal specifies the covariance matrix of all variates within one draw.
Simulating exponential random variables with the same mean interval time with different methods gives rise to different x axis scales How often do we get no-hitters? The number of games played betw...
For this application, it's simply the left end of the desired distribution (scalar). This defaults to 0, and is only changed if your application starts at something other than 0. mu is the mean of the function. size is the sample size. The Poisson distribution has only the one shape parameter: mu. The variance, mean, and frequency are lock ...
I am trying to generate data which follow specified truncated normal distribution. Based on answers here and here, I wrote, lower,upper,mu,sigma,N = 5,15,10,5,10000 samples = scipy.stats.truncnorm....