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  2. Tensor product of modules - Wikipedia

    en.wikipedia.org/wiki/Tensor_product_of_modules

    The binary tensor product is associative: (M 1 ⊗ M 2) ⊗ M 3 is naturally isomorphic to M 1 ⊗ (M 2 ⊗ M 3). The tensor product of three modules defined by the universal property of trilinear maps is isomorphic to both of these iterated tensor products.

  3. Tor functor - Wikipedia

    en.wikipedia.org/wiki/Tor_functor

    [4] Tor R 0 (A, B) ≅ A ⊗ R B for any right R-module A and left R-module B. Tor R i (A, B) = 0 for all i > 0 if either A or B is flat (for example, free) as an R-module. In fact, one can compute Tor using a flat resolution of either A or B; this is more general than a projective (or free) resolution. [5] There are converses to the previous ...

  4. Hilbert's third problem - Wikipedia

    en.wikipedia.org/wiki/Hilbert's_third_problem

    For some purposes, this definition can be made using the tensor product of modules over (or equivalently of abelian groups), while other aspects of this topic make use of a vector space structure on the invariants, obtained by considering the two factors and / to be vector spaces over and taking the tensor product of vector spaces over . This ...

  5. Tensor product - Wikipedia

    en.wikipedia.org/wiki/Tensor_product

    The tensor product of two vector spaces is a vector space that is defined up to an isomorphism.There are several equivalent ways to define it. Most consist of defining explicitly a vector space that is called a tensor product, and, generally, the equivalence proof results almost immediately from the basic properties of the vector spaces that are so defined.

  6. Derived tensor product - Wikipedia

    en.wikipedia.org/wiki/Derived_tensor_product

    In particular, () is the usual tensor product of modules M and N over R. Geometrically, the derived tensor product corresponds to the intersection product (of derived schemes ). Example : Let R be a simplicial commutative ring , Q ( R ) → R be a cofibrant replacement, and Ω Q ( R ) 1 {\displaystyle \Omega _{Q(R)}^{1}} be the module of ...

  7. Bimodule - Wikipedia

    en.wikipedia.org/wiki/Bimodule

    In this interpretation, the category End(R) = Bimod(R, R) is exactly the monoidal category of R-R-bimodules with the usual tensor product over R the tensor product of the category. In particular, if R is a commutative ring, every left or right R-module is canonically an R-R-bimodule, which gives a monoidal embedding of the category R-Mod into ...

  8. Tensor product of Hilbert spaces - Wikipedia

    en.wikipedia.org/wiki/Tensor_product_of_Hilbert...

    Then the von Neumann tensor product of the von Neumann algebras is the strong completion of the set of all finite linear combinations of simple tensor products where for =, This is exactly equal to the von Neumann algebra of bounded operators of H 1 ⊗ H 2 . {\displaystyle H_{1}\otimes H_{2}.}

  9. Symmetric monoidal category - Wikipedia

    en.wikipedia.org/wiki/Symmetric_monoidal_category

    The tensor product is the direct product of objects, and any terminal object (empty product) is the unit object. The category of bimodules over a ring R is monoidal (using the ordinary tensor product of modules), but not necessarily symmetric. If R is commutative, the category of left R-modules is symmetric monoidal. The latter example class ...