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Such games are used to pick out a person from a group, e.g. eeny, meeny, miny, moe. A drawing for the Josephus problem sequence for 500 people and skipping value of 6. The horizontal axis is the number of the person. The vertical axis (top to bottom) is time (the number of cycle). A live person is drawn as green, a dead one is drawn as black. [1]
This is done by taking persons A, C, & D: C+A+D+A = 5+1+8+1=15. (Here we use A because we know that using A to cross both C and D separately is the most efficient.) But, the time has elapsed and person A and B are still on the starting side of the bridge and must cross. So it is not possible for the two slowest (C & D) to cross separately.
Thus if N = 300,000,000 (90% of the US population, with 10% of population being too young to participate) and K = 30 then Degrees of Separation = APL = 19.5 / 3.4 = 5.7 and if N = 7,200,000,000 (90% of the world population, with 10% of population being too young to participate) and K = 30 then Degrees of Separation = APL = 22.7 / 3.4 = 6.7.
In the expression 6/x vision, the numerator (6) is the distance in metres between the subject and the chart and the denominator (x) the distance at which a person with 6/6 acuity would discern the same optotype. Thus, 6/12 means that a person with 6/6 vision would discern the same optotype from 12 metres away (i.e. at twice the distance).
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The event that all 23 people have different birthdays is the same as the event that person 2 does not have the same birthday as person 1, and that person 3 does not have the same birthday as either person 1 or person 2, and so on, and finally that person 23 does not have the same birthday as any of persons 1 through 22. Let these events be ...
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