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Thames Measurement, also known as Thames Tonnage, is a system for measuring ships and boats. It was created in 1855 as a variation of Builder's Old Measurement by the Royal Thames Yacht Club , and was designed for small vessels, such as yachts .
Achilles would then have to move 5 meters, where the tortoise would move 2.5 meters, and so on. Zeno argued that the tortoise would always remain ahead of Achilles. Similarly, Zeno's dichotomy paradox arises from the supposition that to move a certain distance, one would have to move half of it, then half of the remaining distance, and so on ...
The first four partial sums of the series 1 + 2 + 3 + 4 + ⋯.The parabola is their smoothed asymptote; its y-intercept is −1/12. [1]The infinite series whose terms ...
A template for displaying common fractions of the form int+num/den nicely. It supports 0–3 anonymous parameters with positional meaning. Template parameters [Edit template data] Parameter Description Type Status leftmost part 1 Denominator if only parameter supplied. Numerator if 2 parameters supplied. Integer if 3 parameters supplied. If no parameter is specified the template will render a ...
The simplest examples are the golden ratio φ = [1;1,1,1,1,1,...] and √ 2 = [1;2,2,2,2,...], while √ 14 = [3;1,2,1,6,1,2,1,6...] and √ 42 = [6;2,12,2,12,2,12...]. All irrational square roots of integers have a special form for the period; a symmetrical string, like the empty string (for √ 2 ) or 1,2,1 (for √ 14 ), followed by the ...
Name First elements Short description OEIS Mersenne prime exponents : 2, 3, 5, 7, 13, 17, 19, 31, 61, 89, ... Primes p such that 2 p − 1 is prime.: A000043 ...
Set 3-1 has three possible versions: [0 1 1 1 2 T], [0 1 1 T E 1], and [0 T T 1 E 1], where the subscripts indicate adjacency intervals. The normal form is the smallest "slice of pie" (shaded) or most compact form; in this case, [0 1 1 1 2 T ].
Today, a more standard phrasing of Archimedes' proposition is that the partial sums of the series 1 + 1 / 4 + 1 / 16 + ⋯ are: + + + + = +. This form can be proved by multiplying both sides by 1 − 1 / 4 and observing that all but the first and the last of the terms on the left-hand side of the equation cancel in pairs.