Search results
Results from the WOW.Com Content Network
2-Bromobutane is an isomer of 1-bromobutane. Both compounds share the molecular formula C 4 H 9 Br. 2-Bromobutane is also known as sec -butyl bromide or methylethylbromomethane. Because it contains bromine , a halogen, it is part of a larger class of compounds known as alkyl halides .
The molecular formula C 4 H 9 Br, (molar mass: 137.02 g/mol, exact mass: 135.9888 u) may refer to: 1-Bromobutane; 2-Bromobutane; tert-Butyl bromide;
Bromobutane (molecular formula: C 4 H 9 Br, molar mass: 137.02 g/mol) may refer to either of two chemical compounds: 1-Bromobutane ( n -butyl bromide) 2-Bromobutane ( sec -butyl bromide or methylethylbromomethane)
tert-Butyl bromide (also referred to as 2-bromo-2-methylpropane) is an organic compound with the formula Me 3 CBr (Me = methyl). The molecule features a tert-butyl group attached to a bromide substituent. This organobromine compound is used as a standard reagent in synthetic organic chemistry. It is a colorless liquid.
2 Li + C 4 H 9 X → C 4 H 9 Li + LiX where X = Cl, Br. The lithium for this reaction contains 1-3% sodium. When bromobutane is the precursor, the product is a homogeneous solution, consisting of a mixed cluster containing both LiBr and LiBu. 1-Fluorobutane can be obtained by reacting 1-bromobutane with potassium fluoride in ethylene glycol. [5]
Molar mass: 157.010 g·mol −1 Appearance Colourless liquid Odor: Pleasant aromatic odor Density: 1.495 g cm −3, liquid Melting point: −30.8 °C (−23.4 °F ...
Tetrabutylammonium bromide can be prepared by the alkylation of tributylamine with 1-bromobutane. [2] Tetrabutylammonium bromide is used to prepare other salts of the tetrabutylammonium cation by salt metathesis reactions. [6] It serves as a source of bromide ions for substitution reactions. It is a commonly used phase transfer catalyst.
For example, if a sample of bromobutane measured under standard conditions has an observed specific rotation of −9.2°, this indicates that the net effect is due to (9.2°/23.1°)(100%) = 40% of the R enantiomer.