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pulley torque lets simplify this hp*5252/rpm=torque ftlbs motor hp 2 motor rpm 1725 2*5252/1725=6.08 ftlbs torque add a driving pulley 3 inch and a driven pulley 5 inch to this and through reduction we will increase torque. 1725*3/5=1035 rpm 2hp*5252/1035rpm=10.14 or 10 ftlbs torque less ineff. of pulleys motor etc.
A pulley-to-shaft-to-pulley calculation is a mathematical formula used to determine the relationship between the size and speed of two pulleys connected by a shaft. This calculation is important in mechanical engineering and can be used to design systems such as conveyor belts, bicycles, and gearboxes. 2.
The motor pulley is 25.4mm, turning at 100 rpm, with an available 1.4Nm torque. This is connected to the second shaft via belt. The second shaft has an input pulley of 82.5mm. Also on the second shaft is another pulley of 24.5mm. This pulley is connected via belt to a third shaft with a 40.6mm pulley.
Thanks for reaching out ,The Full Question is : You are a mechanical system design engineer of factory you have to design a mechanical system with an electric motor connected to a gearbox which is connected to the belt-pulley system that drives a water pump should run at 200Rpm and 9kw net power should be transmitted to the pump in order to pressurize the water to the desired place for24hour a ...
The variables involved are motor rpm, motor pulley diameter, Pulley B diameter, and Pulley B rpm (which is equal to shaft rpm). The equation for finding Pulley B rpm is mentioned and it is noted that if Pulley B is fixed to the shaft, it will rotate at the same rate. The conversation ends with the individual expressing gratitude for the help.
1,503. 0. The calculation for determining motor shaft RPM using a tachometer is as follows: Motor shaft RPM = (Tachometer RPM) * (Tachometer diameter / Motor shaft diameter) In this case, the calculation would be: Motor shaft RPM = (1400rpm) * (31.5mm/12mm) = 3666.67rpm. It is important to note that this calculation assumes that the tachometer ...
They are considering doubling the size of the drive pulley to solve the issue and are wondering what size to make the driven pulley to maintain the same RPM (around 700-750). The expert suggests that the real issue may be a tight belt or faulty fan bearings, and that increasing the drive pulley would increase the RPM.
103. The ratio of RPM between the motor and fan needs to be 1.5. Therefore you need a 3 inch dia. pully on the motor and a 2 inch on the fan. 3/2=1.5. Check the amps pulled by the motor with this combination to see if you are over driving the motor. Nov 10, 2022.
The formula for calculating the driven pulley size is: Driven Pulley Size = (Driving Pulley Size x Gear Ratio) / Desired RPM. For example, if the driving pulley is 10 inches in diameter, the gear ratio is 3:1, and the desired RPM is 500, the driven pulley size would be (10 x 3) / 500 = 0.06 inches. 2. What is the purpose of calculating the ...
Hi Dr.D the application is a 1953 Delta craftman 28-110 band saw. the band saw wheels are 10" dia on a shaft with a 5" drive wheel, 11 1/2" away is the motor with a shaft speed of 2800 rpm at this time but if I can not get the drive pulley on the motor shaft reach the right rpm then I will look at changing the motor for a 1725 rpm and return a new drive pulley for it.