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One kilogram-force, nominal weight of a 1 kg (2.2 lb) object at sea level on Earth [15] 10 N 50 N Average force to break the shell of a chicken egg from a young hen [16] 10 2 N 720 N Average force of human bite, measured at molars [17] 10 3 N kilonewton (kN) 5 kN The force applied by the engine of a small car during peak acceleration [citation ...
l/m = 1693 × l m /Nec × m/kg, where l/m is the yarn length in metres, l m /Nec is the English cotton count and m/kg is the yarn weight in kilograms. The following length units are defined. Bundle: usually 10 lb (4.5 kg) Thread: a length of 54 in (1.4 m)—the circumference of a warp beam; Lea: 120 yd (110 m) Hank: a length of 7 leas or 840 yd ...
Newton under-estimated the Earth's volume by about 30%, so that his estimate would be roughly equivalent to (4.2 ± 0.5) × 10 24 kg. In the 18th century, knowledge of Newton's law of universal gravitation permitted indirect estimates on the mean density of the Earth, via estimates of (what in modern terminology is known as) the gravitational ...
1 slug = 1 lbf⋅s 2 /ft ≈ 14.59390 kg; Force 1 poundal = force to accelerate 1 pound mass 1 foot/second/second ≈ 0.138 newtons. 1 kip = 1000 lbf ≈ 4.44822 kN; Energy 1 foot-pound ≈ 1.356 J; 1 British thermal unit (Btu) ≈ 1.055 kJ (1,054–1,060 J, depending on which of several definitions of BTU is used)
The measured value of the constant is known with some certainty to four significant digits. In SI units, its value is approximately 6.6743 × 10 −11 m 3 kg −1 s −2. [1] The modern notation of Newton's law involving G was introduced in the 1890s by C. V. Boys.
The solar mass (M ☉) is a standard unit of mass in astronomy, equal to approximately 2 × 10 30 kg (2 nonillion kilograms in US short scale). It is approximately equal to the mass of the Sun. It is often used to indicate the masses of other stars, as well as stellar clusters, nebulae, galaxies and black holes. More precisely, the mass of the ...
On the surface of the Earth, for example, an object with a mass of 50 kilograms weighs 491 newtons, which means that 491 newtons is being applied to keep the object from going into free fall. By contrast, on the surface of the Moon, the same object still has a mass of 50 kilograms but weighs only 81.5 newtons, because only 81.5 newtons is ...
Using PETN, engineers would need 1.0/1.66 (or 0.60) kg to obtain the same effects as 1 kg of TNT. With ANFO or ammonium nitrate, they would require 1.0/0.74 (or 1.35) kg or 1.0/0.32 (or 3.125) kg, respectively. Calculating a single RE factor for an explosive is, however, impossible. It depends on the specific case or use.