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When I try to divide 1/60 or 1/(60*60) it gives 0. Even in debugger window. Even in debugger window. I am a bit confused what it could be, because 2/3 or 2.5/6 give results.
Neither 0.1 nor 0.2 are exactly representable in binary floating point. And nor is 0.3. A number is exactly representable if it is of the form a/b where a and b are an integers and b is a power of 2.
Division of both natural numbers and real numbers upholds the axiom that (n+d)/d = (n/d)+1. Division of real numbers also upholds (-n)/d = - (n/d), an axiom which is meaningless with natural numbers. It is not possible to have a division operator which is closed on integers and upholds both axioms.
Usually, the first two numbers respresent a major and a minor version, i.e. 1.0 for the first real release, 1.1 for some important bugfixes and minor new features, 2.0 for a big new feature release. The third number can refer to a "really minor" version, or revision. 1.0.1 is just a very small bugfix to 1.0.0 for example.
1/3 uses integer division as both sides are integers. You need at least one of them to be float or double. If you are entering the values in the source code like your question, you can do 1.0/3; the 1.0 is a double. If you get the values from elsewhere you can use (double) to turn the int into a double.
Because the conversion to float happens after the division has been done. You need: float percentage = ((float) totalOptCount) / totalRespCount; You should be able to format using something like: String str = String.format("%2.02f", percentage); edited Feb 8, 2011 at 10:45. Jesper.
4. Here is the Python code. The function coef computes the finite divided difference coefficients, and the function Eval evaluates the interpolation at a given node. import numpy as np. import matplotlib.pyplot as plt. def coef(x, y): '''x : array of data points. y : array of f(x) '''. x.astype(float)
z = x/y. else: z = 0. or you can use : z = ( x / y ) if y != 0 else 0. If you are trying to divide two lists of integers you may use : z = [j/k if k else 0 for j, k in zip(x, y)] where here, x and y are two lists of integers. edited Jan 2, 2021 at 16:26.
When converting Number values to strings in JavaScript, the default is to use just enough digits to uniquely distinguish the Number value. 1 This means that when a number is displayed as “0.1”, that does not mean it is exactly 0.1, just that it is closer to 0.1 than any other Number value is, so displaying just “0.1” tells you it is ...
For example, 1 // 0.2 evaluates to 4. However 1 / 0.2 returns 5, and math.floor(1 / 2) also returns 5. It's giving a number one less than what integer division should. The // operator returns a 5 if you divide 10 by 2, but 1 divided 0.2 does not work correctly. This problem comes up other times I use the // operator to divide floating point ...