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The leap year problem (also known as the leap year bug or the leap day bug) is a problem for both digital (computer-related) and non-digital documentation and data storage situations which results from errors in the calculation of which years are leap years, or from manipulating dates without regard to the difference between leap years and ...
The last modification date stamp (and with DELWATCH 2.0+ also the file deletion date stamp, and since DOS 7.0+ optionally also the last access date stamp and creation date stamp), are stored in the directory entry with the year represented as an unsigned seven bit number (0–127), relative to 1980, and thereby unable to indicate any dates in ...
Microsoft Excel (using the default 1900 Date System) cannot display dates before the year 1900, although this is not due to a two-digit integer being used to represent the year: Excel uses a floating-point number to store dates and times. The number 1.0 represents the first second of January 1, 1900, in the 1900 Date System (or January 2, 1904 ...
Using a signed 64-bit value introduces a new wraparound date that is over twenty times greater than the estimated age of the universe: approximately 292 billion years from now. [11] The ability to make computations on dates is limited by the fact that tm_year uses a signed 32-bit integer value starting at 1900 for the year. This limits the year ...
Or simply, using the simpler parameter names, compatible with {{Age in years, months and days}}: {{Age in years, months, weeks and days |month = 1 |day = 1 |year = 1 }} → 2023 years, 11 months, 2 weeks and 6 days; Alternatively, the first set of parameters can be left out to get the time left until a future date, such as the next Wikipedia ...
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Excel maintains 15 figures in its numbers, but they are not always accurate; mathematically, the bottom line should be the same as the top line, in 'fp-math' the step '1 + 1/9000' leads to a rounding up as the first bit of the 14 bit tail '10111000110010' of the mantissa falling off the table when adding 1 is a '1', this up-rounding is not undone when subtracting the 1 again, since there is no ...
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