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The ideal gas law is used for these calculations. Often, but not always, the standard temperature and pressure (STP) are taken as 0 °C and 1 bar and used as the conditions for gas stoichiometric calculations. Gas stoichiometry calculations solve for the unknown volume or mass of a gaseous product or reactant.
Constant level of this surface is identified from the equation (,) =, where is called as the stoichiometric mixture fraction which is obtained by setting = = (since if they were react to consume fuel and oxygen, only on the stoichiometric locations both fuel and oxygen will be consumed completely) in the definition of to obtain
where the pressure, p, is the atmospheric pressure, V is the measured volume of the vessel, T is the absolute temperature of the hot bath, and R is the gas constant. The molecular weight of the chemical is then simply the mass in grams of the vapor within the vessel divided by the calculated number of mole.
energy/mass of fuel; energy/volume of the fuel; There are two kinds of enthalpy of combustion, called high(er) and low(er) heat(ing) value, depending on how much the products are allowed to cool and whether compounds like H 2 O are allowed to condense. The high heat values are conventionally measured with a bomb calorimeter. Low heat values are ...
For example, a calculation of the mass of natural gas as fuel — which often contains carbon dioxide (CO 2), nitrogen (N 2), and various alkanes — includes the mass of the carbon dioxide, nitrogen and all alkanes in determining the value of m fuel. [2] For pure octane the stoichiometric mixture is approximately 15.1:1, or λ of 1.00 exactly.
How much gas is present could be specified by giving the mass instead of the chemical amount of gas. Therefore, an alternative form of the ideal gas law may be useful. The chemical amount, n (in moles), is equal to total mass of the gas (m) (in kilograms) divided by the molar mass, M (in kilograms per mole): =.
where w C, w H, w S, w O refer to the mass fraction of each element in the fuel oil, sulfur burning to SO 2, and AFR mass refers to the air-fuel ratio in mass units. For 1 kg of fuel oil containing 86.1% C, 13.6% H, 0.2% O, and 0.1% S the stoichiometric mass of air is 14.56 kg, so AFR = 14.56. The combustion product mass is then 15.56 kg.
The stoichiometric concentration of methane in oxygen is therefore 1/(1+2), which is 33 percent. Any stoichiometric mixture of methane and oxygen will lie on the straight line between pure nitrogen (and zero percent methane) and 33 percent methane (and 67 percent oxygen) – this is shown as the red stoichiometric line.