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Volume to mass conversions for some common cooking ingredients; ingredient density g/mL [note 5] metric cup 250 mL imperial cup ≈284 mL U.S. customary cup ≈237 mL [note 6] g oz g oz g oz water [note 7] 1 [note 8] 249–250 8.8 283–284 10 236–237 8.3 [note 9] granulated sugar 0.8 [20] 200 7.0 230 8.0 190 6.7 wheat flour 0.5–0.6 [20 ...
{{convert|100|lb|kg}} → 100 pounds (45 kg) The unit-codes should be treated as case-sensitive: {{convert|100|Mm|mm}} → 100 megametres (1.0 × 10 11 mm) The output of {{convert}} can display multiple converted units, if further unit-codes are specified after the second unnamed parameter (without the pipe separator). Typical combination ...
Conversions between units in the metric system are defined by their prefixes (for example, 1 kilogram = 1000 grams, 1 milligram = 0.001 grams) and are thus not listed in this article. Exceptions are made if the unit is commonly known by another name (for example, 1 micron = 10 −6 metre).
In the United States, the standard drink contains 0.6 US fluid ounces (18 ml) of alcohol. This is approximately the amount of alcohol in a 12-US-fluid-ounce (350 ml) glass of beer, a 5-US-fluid-ounce (150 ml) glass of wine, or a 1.5-US-fluid-ounce (44 ml) glass of a 40% ABV (80 US proof) spirit.
One momme = 4.340 g/m 2; 8 mommes is approximately 1 ounce per square yard or 35 g/m 2. The momme is based on the standard width of silk of 45 inches (1.1 m) wide (though silk is regularly produced in 55-inch (1.4 m) widths and uncommonly in larger widths).
[1] [2] [3] It is defined as the number of millilitres (mL) of pure ethanol present in 100 mL (3.5 imp fl oz; 3.4 US fl oz) of solution at 20 °C (68 °F). The number of millilitres of pure ethanol is the mass of the ethanol divided by its density at 20 °C (68 °F), which is 0.78945 g/mL (0.82353 oz/US fl oz; 0.79122 oz/imp fl oz; 0.45633 oz ...
The gram (originally gramme; [1] SI unit symbol g) is a unit of mass in the International System of Units (SI) equal to one thousandth of a kilogram.. Originally defined as of 1795 as "the absolute weight of a volume of pure water equal to the cube of the hundredth part of a metre [1 cm 3], and at the temperature of melting ice", [2] the defining temperature (≈0 °C) was later changed to 4 ...
Knowing the amount of extract in 100 grams (3.5 oz) of wort before fermentation and the number of grams of extract in 100 grams (3.5 oz) of beer at its completion, the amount alcohol (in grams) formed during the fermentation can be determined. The formula follows, attributed to Balling [1]: 427