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As of C++20, the free functions std::erase and std::erase_if are provided for STL containers. These convenience functions can be used to perform correct erasure of elements without requiring the programmer to explicitly use the erase-remove idiom. [5]
In C++, associative containers are a group of class templates in the standard library of the C++ programming language that implement ordered associative arrays. [1] Being templates, they can be used to store arbitrary elements, such as integers or custom classes.
Due to their usefulness, they were later included in several other implementations of the C++ Standard Library (e.g., the GNU Compiler Collection's (GCC) libstdc++ [2] and the Visual C++ (MSVC) standard library). The hash_* class templates were proposed into C++ Technical Report 1 (C++ TR1) and were accepted under names unordered_*. [3]
ldstr <string> Push a string object for the literal string. Object model instruction 0xD0 ldtoken <token> Convert metadata token to its runtime representation. Object model instruction 0xFE 0x07 ldvirtftn <method> Push address of virtual method on the stack. Object model instruction 0xDD leave <int32 (target)> Exit a protected region of code.
EDOM: A parameter was outside a function's domain, e.g. sqrt (-1) ERANGE: A result outside a function's range, e.g. strtol ("0xfffffffff", NULL, 0) on systems with a 32-bit wide long
The loop calls the Iterator::next method on the iterator before executing the loop body. If Iterator::next returns Some(_), the value inside is assigned to the pattern and the loop body is executed; if it returns None, the loop is terminated.
A string is defined as a contiguous sequence of code units terminated by the first zero code unit (often called the NUL code unit). [1] This means a string cannot contain the zero code unit, as the first one seen marks the end of the string. The length of a string is the number of code units before the zero code unit. [1]
Proof. We need to prove that if you add a burst of length to a codeword (i.e. to a polynomial that is divisible by ()), then the result is not going to be a codeword (i.e. the corresponding polynomial is not divisible by ()).