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In computer science and formal methods, a SAT solver is a computer program which aims to solve the Boolean satisfiability problem.On input a formula over Boolean variables, such as "(x or y) and (x or not y)", a SAT solver outputs whether the formula is satisfiable, meaning that there are possible values of x and y which make the formula true, or unsatisfiable, meaning that there are no such ...
A variant of the 3-satisfiability problem is the one-in-three 3-SAT (also known variously as 1-in-3-SAT and exactly-1 3-SAT). Given a conjunctive normal form with three literals per clause, the problem is to determine whether there exists a truth assignment to the variables so that each clause has exactly one TRUE literal (and thus exactly two ...
In computer science and mathematical logic, satisfiability modulo theories (SMT) is the problem of determining whether a mathematical formula is satisfiable.It generalizes the Boolean satisfiability problem (SAT) to more complex formulas involving real numbers, integers, and/or various data structures such as lists, arrays, bit vectors, and strings.
#SAT is harder than SAT in the sense that, once the total number of solutions to a Boolean formula is known, SAT can be decided in constant time. However, the converse is not true, because knowing a Boolean formula has a solution does not help us to count all the solutions , as there are an exponential number of possibilities.
The MAX-SAT problem is OptP-complete, [1] and thus NP-hard, since its solution easily leads to the solution of the boolean satisfiability problem, which is NP-complete. It is also difficult to find an approximate solution of the problem, that satisfies a number of clauses within a guaranteed approximation ratio of the optimal solution.
For every R, add clauses representing f R (x i1,...,x iq) using 2 q SAT clauses. Clauses of length q are converted to length 3 by adding new (auxiliary) variables e.g. x 2 ∨ x 10 ∨ x 11 ∨ x 12 = ( x 2 ∨ x 10 ∨ y R) ∧ ( y R ∨ x 11 ∨ x 12). This requires a maximum of q2 q 3-SAT clauses. If z ∈ L then there is a proof π such ...
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