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  2. Vieta's formulas - Wikipedia

    en.wikipedia.org/wiki/Vieta's_formulas

    Vieta's formulas applied to quadratic and cubic polynomials: The roots , of the quadratic polynomial () ... which are Vieta's formula's for = ...

  3. Cubic equation - Wikipedia

    en.wikipedia.org/wiki/Cubic_equation

    By Vieta's formulas, s 0 is known to be zero in the case of a depressed cubic, and − ⁠ b / a ⁠ for the general cubic. So, only s 1 and s 2 need to be computed. They are not symmetric functions of the roots (exchanging x 1 and x 2 exchanges also s 1 and s 2 ), but some simple symmetric functions of s 1 and s 2 are also symmetric in the ...

  4. Viète's formula - Wikipedia

    en.wikipedia.org/wiki/Viète's_formula

    Viète's formula, as printed in Viète's Variorum de rebus mathematicis responsorum, liber VIII (1593). In mathematics, Viète's formula is the following infinite product of nested radicals representing twice the reciprocal of the mathematical constant π: = + + + It can also be represented as = = ⁡ +.

  5. Elementary symmetric polynomial - Wikipedia

    en.wikipedia.org/wiki/Elementary_symmetric...

    The characteristic polynomial of a square matrix is an example of application of Vieta's formulas. The roots of this polynomial are the eigenvalues of the matrix . When we substitute these eigenvalues into the elementary symmetric polynomials, we obtain – up to their sign – the coefficients of the characteristic polynomial, which are ...

  6. Vieta jumping - Wikipedia

    en.wikipedia.org/wiki/Vieta_jumping

    Using Vieta's formulas, show that this implies the existence of a smaller solution, hence a contradiction. Example. Problem #6 at IMO 1988: Let a and b be positive integers such that ab + 1 divides a 2 + b 2. Prove that ⁠ a 2 + b 2 / ab + 1 ⁠ is a perfect square. [8] [9] Fix some value k that is a non-square positive integer.

  7. Quartic function - Wikipedia

    en.wikipedia.org/wiki/Quartic_function

    It also follows from Vieta's formulas, together with the fact that we are working with a depressed quartic, that r 1 + r 2 + r 3 + r 4 = 0. (Of course, this also follows from the fact that r 1 + r 2 + r 3 + r 4 = −s + s.) Therefore, if α, β, and γ are the roots of the resolvent cubic, then the numbers r 1, r 2, r 3, and r 4 are such that

  8. Geometrical properties of polynomial roots - Wikipedia

    en.wikipedia.org/wiki/Geometrical_properties_of...

    Vieta's formulas – Relating coefficients and roots of a polynomial Cohn's theorem relating the roots of a self-inversive polynomial with the roots of the reciprocal polynomial of its derivative. Notes

  9. Cubic function - Wikipedia

    en.wikipedia.org/wiki/Cubic_function

    The derivative of a cubic function is a quadratic function. A cubic function with real coefficients has either one or three real roots (which may not be distinct); [1] all odd-degree polynomials with real coefficients have at least one real root. The graph of a cubic function always has a single inflection point.