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  2. Equiangular polygon - Wikipedia

    en.wikipedia.org/wiki/Equiangular_polygon

    An equiangular hexagon with 1:2 edge length ratios, with equilateral triangles. [6] This is spirolateral 2 120°. Direct equiangular hexagons, <6> and <6/2>, have 120° and 60° internal angles respectively. 120° internal angles of an equiangular hexagon, <6> An equiangular hexagon with integer side lengths may be tiled by unit equilateral ...

  3. Hexagon - Wikipedia

    en.wikipedia.org/wiki/Hexagon

    A principal diagonal of a hexagon is a diagonal which divides the hexagon into quadrilaterals. In any convex equilateral hexagon (one with all sides equal) with common side a, there exists [11]: p.184, #286.3 a principal diagonal d 1 such that and a principal diagonal d 2 such that

  4. Regular polygon - Wikipedia

    en.wikipedia.org/wiki/Regular_polygon

    A non-convex regular polygon is a regular star polygon. The most common example is the pentagram, which has the same vertices as a pentagon, but connects alternating vertices. For an n-sided star polygon, the Schläfli symbol is modified to indicate the density or "starriness" m of the polygon, as {n/m}.

  5. Polygon - Wikipedia

    en.wikipedia.org/wiki/Polygon

    In either case, the area formula is correct in absolute value. This is commonly called the shoelace formula or surveyor's formula. [6] The area A of a simple polygon can also be computed if the lengths of the sides, a 1, a 2, ..., a n and the exterior angles, θ 1, θ 2, ..., θ n are known, from:

  6. Shoelace formula - Wikipedia

    en.wikipedia.org/wiki/Shoelace_formula

    Shoelace scheme for determining the area of a polygon with point coordinates (,),..., (,). The shoelace formula, also known as Gauss's area formula and the surveyor's formula, [1] is a mathematical algorithm to determine the area of a simple polygon whose vertices are described by their Cartesian coordinates in the plane. [2]

  7. Bicentric quadrilateral - Wikipedia

    en.wikipedia.org/wiki/Bicentric_quadrilateral

    This formula cannot be used if the quadrilateral is a right kite, since the denominator is zero in that case. If M, N are the midpoints of the diagonals, and E, F are the intersection points of the extensions of opposite sides, then the area of a bicentric quadrilateral is given by

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  9. Euclidean tilings by convex regular polygons - Wikipedia

    en.wikipedia.org/wiki/Euclidean_tilings_by...

    With a final vertex 3 4.6, 4 more contiguous equilateral triangles and a single regular hexagon. However, this notation has two main problems related to ambiguous conformation and uniqueness [2] First, when it comes to k-uniform tilings, the notation does not explain the relationships between the vertices. This makes it impossible to generate a ...