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The default calculates an age—the day of the second date is not included in the calculation. A duration including the second date is calculated if |duration=on is used. {{age in years and days|1 Jan 2011|31 Dec 2012}} → 1 year, 365 days {{age in years and days|1 Jan 2011|31 Dec 2012|sep=and}} → 1 year and 365 days
This template returns the number of full years, surplus months, and surplus days between two specified dates. If the second set of parameters is not included, it will return the number of years, months and days between a specified date and today's date. Template parameters [Edit template data] Parameter Description Type Status Year ('from' date) 1 year The year of the (first) date Number ...
Short format: dd/mm/yyyy (Day first, month number and year in left-to-right writing direction) in Afar, French and Somali ("d/m/yy" is a common alternative). Gregorian dates follow the same rules but tend to be written in the yyyy/m/d format (Day first, month number, and year in right-to-left writing direction) in Arabic language .
An extra day added as a holiday at the end of the year (after December 28, i.e. equal to December 31 Gregorian), sometimes called "Year Day", does not belong to any week and brings the total to 365 days. Each year coincides with the corresponding Gregorian year, so January 1 in the Cotsworth calendar always falls on Gregorian January 1.
This template returns the number of full years, surplus months, and surplus days between two specified dates. If the second set of parameters is not included, it will return the number of years, months and days between a specified date and today's date. Template parameters Parameter Description Type Status Year ('from' date) 1 year The year of the (first) date Number required Month ('from ...
This convention accounts for days in the period based on the portion in a leap year and the portion in a non-leap year. The days in the numerators are calculated on a Julian day difference basis. In this convention the first day of the period is included and the last day is excluded. The CouponFactor uses the same formula, replacing Date2 by Date3.
The algorithm for the day-of-week of 1 Jan can be proven using modulo arithmetic. The main point is that because 365 % 7 = 1, each year adds 1 day to the progression. The rest is adjustment for leap year. The century-based versions have 36525 % 7 = 6. The table of month offsets show a divergence in February due to the leap year.
Subtract the weekday number from the ordinal day of the year. Add 10. Divide by 7, discard the remainder. If the week number thus obtained equals 0, it means that the given date belongs to the preceding (week-based) year. If a week number of 53 is obtained, one must check that the date is not actually in week 1 of the following year. Formula