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With substantial evidence, Hugh Huxley formally proposed the mechanism for sliding filament which is variously called swinging cross-bridge model, cross-bridge theory or cross-bridge model. [ 3 ] [ 30 ] (He himself preferred the name "swinging crossbridge model", because, as he recalled, "it [the discovery] was, after all, the 1960s". [ 2 ] )
Cross-bridge cycle. Cross-bridge cycling is a sequence of molecular events that underlies the sliding filament theory. A cross-bridge is a myosin projection, consisting of two myosin heads, that extends from the thick filaments. [1] Each myosin head has two binding sites: one for adenosine triphosphate (ATP) and another for actin.
Activation consists of phosphorylation of a serine on position 19 (Ser19) on the MLC 20 light chain, which causes a conformational change that increases the angle in the neck domain of the myosin heavy chain, [8] which corresponds to the part of the cross-bridge cycle where the myosin head is unattached to the actin filament and relocates to ...
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The roots of periodization come from Hans Selye's model, known as the General adaptation syndrome (GAS). The GAS describes three basic stages of response to stress: (a) the Alarm stage, involving the initial shock of the stimulus on the system, (b) the Resistance stage, involving the adaptation to the stimulus by the system, and (c) the Exhaustion stage, in that repairs are inadequate, and a ...
A Hamiltonian cycle, Hamiltonian circuit, vertex tour or graph cycle is a cycle that visits each vertex exactly once. A graph that contains a Hamiltonian cycle is called a Hamiltonian graph . Similar notions may be defined for directed graphs , where each edge (arc) of a path or cycle can only be traced in a single direction (i.e., the vertices ...
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Then, A must cross next, since we assume we should choose the fastest to make the solo-cross. Then we are at the second, or middle, pair-crossing so C and D must go. Then we choose to send the fastest back, which is B. A and B are now on the start side and must cross for the last pair-crossing. This gives us, B+A+D+B+B = 2+1+8+2+2 = 15.