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  2. How to Convert Lbm/ft^3 to kg/m^3? - Physics Forums

    www.physicsforums.com/threads/how-to-convert-lbm-ft-3-to-kg-m-3.965139

    The formula for converting lb/ft^3 to kg/m^3 is: kg/m^3 = lb/ft^3 x 16.01846. 3. Can you provide an example of converting lb/ft^3 to kg/m^3? Let's say we have a value of 10 lb/ft^3. To convert this to kg/m^3, we would multiply 10 by 16.01846, which gives us 160.1846 kg/m^3. 4.

  3. Total Work (Pumping Oil from a Tank). - Physics Forums

    www.physicsforums.com/threads/total-work-pumping-oil-from-a-tank.75301

    "A fuel tank is an upright cylinder, buried so that its circular top is 10 feet beneath ground level. The tank has a radius of 5 feet and is 15 feet high, although the current oil level is only 6 feet deep. Calculate the work required to pump all of the oil to the surface. Oil weighs 50 lb/ft^3." What I did was to first calculate the volume of ...

  4. Work Required to Empty a Hemispherical Tank - Physics Forums

    www.physicsforums.com/threads/work-required-to-empty-a-hemispherical-tank.382724

    The work required can be calculated using the formula W = mgh, where W is the work in joules, m is the mass of the fluid being drained in kilograms, g is the acceleration due to gravity in meters per second squared, and h is the height of the water column in meters. For a hemispherical tank, the height (h) can be calculated using the formula h ...

  5. Calculate Work Homework: Hemispherical Tank Full of Water -...

    www.physicsforums.com/threads/calculate-work-homework-hemispherical-tank-full...

    The formula for calculating the work required to empty a hemispherical tank full of water is W = (2/3) x π x ρ x g x r^3, where W is the work, π is the mathematical constant pi, ρ is the density of water, g is the acceleration due to gravity, and r is the radius of the tank.

  6. Solve Hydrostatic Force w/ Triangle Plate - Math Homework -...

    www.physicsforums.com/threads/solve-hydrostatic-force-w-triangle-plate-math...

    The width of the triangle can be found using the ratio w/8 = (9-x)/6, where x is the depth measured from the surface. The weight density of water, 62.5 lb/ft^3, represents rho*g in the equation. The integral needs to be corrected for the width and the depth coordinate, which should be x-3. The correct integral is F = \int

  7. Chapter 11 FLUID STATICS - Physics Forums

    www.physicsforums.com/attachments/chapter-11-pdf.25837

    Analysis The average pressure on a surface is the pressure at the centroid (midpoint) of the surface, and is determined to be. Pave = r gh C = r g ( h / 2) 2 æ 1 lbf ö = ( 62.4 lbm/ft 3 )( 32.2 ft/s )( 8/ 2 ft) ç ÷ è 32.2 lbm × ft/s 2 ø. 2 = 249 .6 lbf/ft. Then the resultant hydrostatic force acting on the dam becomes.

  8. Work to Pump Water Out of Tank: Find W w/ 62.5 lb/ft3 - Physics...

    www.physicsforums.com/threads/work-to-pump-water-out-of-tank-find-w-w-62-5-lb...

    The weight of water in a tank can be calculated by multiplying the volume of water in the tank by its density. In this case, the density of water is given as 62.5 lb/ft3. So, if the volume of water in the tank is known, the weight can be easily calculated using this formula. 2.

  9. Finding the force of water in a pool on a vertical wall - Physics...

    www.physicsforums.com/threads/finding-the-force-of-water-in-a-pool-on-a...

    The force of water in a pool on a vertical wall can be calculated using the formula F = ρgh, where F is the force in newtons, ρ is the density of water in kilograms per cubic meter (kg/m 3), g is the acceleration due to gravity (9.8 m/s 2), and h is the depth of the water in meters. 3. Does the height of the water affect the force on the ...