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Base 1: the first character is numbered 1, and so on. Any leading or trailing whitespace is removed from the string before searching. If the requested position is negative, this function will search the string counting from the last character. In other words, number = -1 is the same as asking for the last character of the string.
This template looks for a word in a comma-separated list of words. It returns a True (found) or False (not found) value. By default, the True-value returned is the found word itself; the False-value is a blank string. {{Str find word |source=alpha, foo, bar |word=foo}} (True) → foo {{Str find word |source=alpha, foo, bar |word=nov}} (False) →
This is the {{Str startswith}} meta-template.. It returns "yes" if the second parameter is the start of the first parameter. Both parameters are trimmed before use. Examples
A simple and inefficient way to see where one string occurs inside another is to check at each index, one by one. First, we see if there is a copy of the needle starting at the first character of the haystack; if not, we look to see if there's a copy of the needle starting at the second character of the haystack, and so forth.
A template to find the numeric position of first appearance of ''sub_string'' in ''text'' Template parameters [Edit template data] Parameter Description Type Status Text 1 The text to search within String required Sub_string 2 The string to be searched within the text String required See also
In object-oriented languages, string functions are often implemented as properties and methods of string objects. In functional and list-based languages a string is represented as a list (of character codes), therefore all list-manipulation procedures could be considered string functions.
No two edges starting out of a node can have string-labels beginning with the same character. The string obtained by concatenating all the string-labels found on the path from the root to leaf i {\displaystyle i} spells out suffix S [ i . . n ] {\displaystyle S[i..n]} , for i {\displaystyle i} from 1 {\displaystyle 1} to n {\displaystyle n} .