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[15] From 1967 to 1969, Kaplansky wrote the mathematics section of Encyclopædia Britannica. [16] [17] [18] Kaplansky was the Director of the Mathematical Sciences Research Institute from 1984 to 1992, and the President of the American Mathematical Society from 1985 to 1986. [19] Kaplansky was also an accomplished amateur musician.
People named Kaplansky (Polish: Kapłański (feminine Kapłańska), Russian: Капланский, also Kaplanski (feminine Kaplanska)) include: Abraham Kaplansky (1860–1939), Canadian printer; Kalmen Kaplansky (1912–1997), Canadian labour and human rights activist; Irving Kaplansky (1917–2006), Canadian mathematician Kaplansky density ...
Kaplansky's zero divisor conjecture states: The group ring K[G] does not contain nontrivial zero divisors, that is, it is a domain. Two related conjectures are known as, respectively, Kaplansky's idempotent conjecture: K[G] does not contain any non-trivial idempotents, i.e., if a 2 = a, then a = 1 or a = 0.
In April 2015, Kemper acquired Alliance United Insurance Company, one of the fastest growing auto insurance providers in the State of California.Source: [14] In July 2018, Kemper acquired Infinity Property and Casualty Corporation (NASDAQ: IPCC), an auto insurance provider focused on serving the specialty, nonstandard segment, in a cash and stock transaction valued at approximately $1.4 billion.
CNA Financial Corporation is a financial corporation based in Chicago, Illinois, United States.Its principal subsidiary, Continental Casualty Company (CCC), was founded in 1897, and The Continental Insurance Company (CIC) was organized in 1853. [2]
In 2009, the practice found that some 40 percent of its patients dropped their Suboxone regimen after a year. Some transferred to methadone; others left the program after losing their health insurance. Fingerhood said another major reason was the pressure from friends and relatives who considered Suboxone a “cop-out.”
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The Kaplansky conjecture predicts that for an integral domain and a torsion-free group the only idempotents in [] are ,. Each such idempotent p {\displaystyle p} gives a projective R [ G ] {\displaystyle R[G]} module by taking the image of the right multiplication with p {\displaystyle p} .
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