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  2. Fuss–Catalan number - Wikipedia

    en.wikipedia.org/wiki/Fuss–Catalan_number

    An example of legal and illegal permutations can be better demonstrated by a specific problem such as balanced brackets (see Dyck language). A general problem is to count the number of balanced brackets (or legal permutations) that a string of m open and m closed brackets forms (total of 2m brackets). By legally arranged, the following rules apply:

  3. Lehmer code - Wikipedia

    en.wikipedia.org/wiki/Lehmer_code

    The usual way to prove that there are n! different permutations of n objects is to observe that the first object can be chosen in n different ways, the next object in n − 1 different ways (because choosing the same number as the first is forbidden), the next in n − 2 different ways (because there are now 2 forbidden values), and so forth.

  4. Catalan number - Wikipedia

    en.wikipedia.org/wiki/Catalan_number

    A permutation w is called stack-sortable if S(w) = (1, ..., n), where S(w) is defined recursively as follows: write w = unv where n is the largest element in w and u and v are shorter sequences, and set S(w) = S(u)S(v)n, with S being the identity for one-element sequences. C n is the number of permutations of {1, ..., n} that avoid the ...

  5. Permutation - Wikipedia

    en.wikipedia.org/wiki/Permutation

    An exceedance of a permutation σ 1 σ 2...σ n is an index j such that σ j > j. If the inequality is not strict (that is, σ j ≥ j), then j is called a weak exceedance. The number of n-permutations with k exceedances coincides with the number of n-permutations with k descents. [46]

  6. Twelvefold way - Wikipedia

    en.wikipedia.org/wiki/Twelvefold_way

    The formula counting all functions N → X is not useful here, because the number of them grouped together by permutations of N varies from one function to another. Rather, as explained under combinations , the number of n -multicombinations from a set with x elements can be seen to be the same as the number of n -combinations from a set with x ...

  7. Inclusion–exclusion principle - Wikipedia

    en.wikipedia.org/wiki/Inclusion–exclusion...

    The number of permutations satisfying the restrictions is thus: 4! − (12 + 6 + 0 + 0) + (4) = 24 − 18 + 4 = 10. The final 4 in this computation is the number of permutations having both properties P 1 and P 2. There are no other non-zero contributions to the formula.

  8. Balls into bins problem - Wikipedia

    en.wikipedia.org/wiki/Balls_into_bins_problem

    The balls into bins (or balanced allocations) problem is a classic problem in probability theory that has many applications in computer science. The problem involves m balls and n boxes (or "bins").

  9. Inversion (discrete mathematics) - Wikipedia

    en.wikipedia.org/wiki/Inversion_(discrete...

    The inversions of this permutation using element-based notation are: (3, 1), (3, 2), (5, 1), (5, 2), and (5,4). In computer science and discrete mathematics , an inversion in a sequence is a pair of elements that are out of their natural order .