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@SenthilKumaran If the resulting string requires separate items such as when passing a list of files to a process, then "" has to be changed to " " (notice the space between the quotes). Otherwise, you end up with a contiguous string ("123" instead of "1 2 3").
The string or node provided may only consist of the following Python literal structures: strings, bytes, numbers, tuples, lists, dicts, sets, booleans, None and Ellipsis. This can be used for evaluating strings containing Python values without the need to parse the values oneself.
So, range based for loop in this example , when the python reach the last word of your list, it should'nt add "-" to your concenated_string. If its not last word of your string always append "-" string to your concenated_string variable.
Given the list ['a','ab','abc','bac'], I want to compute a list with strings that have 'ab' in them. I.e. the result is ['ab','abc']. How can this be done in Python?
Without looping through the entire character string and/or using RegEx's (unless those are the most efficient), how should I go about this in a pythonic manner? This is very similar to another SO question, but I need to check for the existence of the ENTIRE val string anywhere in the list. It would also be great to return the index / indices of ...
As sort() sorts the list in place (ie, changes the list directly), it doesn't return the sorted list, and actually doesn't return anything, so your print statement prints None. If you saved your list to a variable, say x, called x.sort(), then print(x), you would see the sorted list. –
Though my solution may be "good enough" solution to his particular problem, and is a good general way to check if any strings in a list are found in another string, keep in mind that this is all that this solution does. It does not care WHERE the string is found e.g. in the ending of the string. If this is important, as is often the case with ...
You can use numpy to convert a list directly to a floating array or matrix. import numpy as np list_ex = [1, 0] # This a list list_int = np.array(list_ex) # This is a numpy integer array If you want to convert the integer array to a floating array then add 0. to it. list_float = np.array(list_ex) + 0. # This is a numpy floating array
Also, starting from Python 3.5 (thanks to the awesome PEP 448) it's now possible to build a list from any iterable by unpacking it to an empty list literal: >>> [*'abc'] ['a', 'b', 'c'] This is neater, and in some cases more efficient than calling list constructor directly.
For Python 3, I do the same kind of thing as shxfee's answer: def print_list(my_list): print('\n'.join(my_list)) a = ['foo', 'bar', 'baz'] print_list(a) which outputs. foo bar baz As an aside, I use a similar helper function to quickly see columns in a pandas DataFrame. def print_cols(df): print('\n'.join(df.columns))