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The puzzle proved popular, and Sulzberger himself authored a Times puzzle before the year was out. [11] In 1950, the crossword became a daily feature. That first daily puzzle was published without an author line, and as of 2001 the identity of the author of the first weekday Times crossword remained unknown. [13]
These numbers, borrowing crossword terminology, are commonly called "clues". The objective of the puzzle is to insert a digit from 1 to 9 inclusive into each white cell so that the sum of the numbers in each entry matches the clue associated with it and that no digit is duplicated in any entry.
Crossword-like puzzles, for example Double Diamond Puzzles, appeared in the magazine St. Nicholas, published since 1873. [32] Another crossword puzzle appeared on September 14, 1890, in the Italian magazine Il Secolo Illustrato della Domenica. It was designed by Giuseppe Airoldi and titled "Per passare il tempo" ("To pass the time"). Airoldi's ...
The last puzzle in "Pencilwise" has generally been "The World's Most Ornery Crossword," a large standard crossword puzzle which has two sets of clues spanning three pages. One set, which is revealed by folding one page in half to hide the second page, consists of "Hard" clues (three stars), while the clues under this fold are "Easy" (one star ...
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An acrostic puzzle published in State Magazine in 1986. An acrostic is a type of word puzzle, related somewhat to crossword puzzles, that uses an acrostic form. It typically consists of two parts. The first part is a set of lettered clues, each of which has numbered blanks representing the letters of the answer.
The solver is given a grid and a list of words. To solve the puzzle correctly, the solver must find a solution that fits all of the available words into the grid. [1] [2] [8] [9] Generally, these words are listed by number of letters, and further alphabetically. [2] [8] Many times, one word is filled in for the solver to help them begin the ...
For example, if 12 across and 7 down both have three digits and the clue for 12 across is "7 down times 2", one can work out that (i) the last digit of 12 across must be even, (ii) the first digit of 7 down must be 1, 2, 3 or 4, and (iii) the first digit of 12 across must be between 2 and 9 inclusive.
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