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2,4,6-Tribromoaniline can be prepared by treating bromine water with aniline in a solution of acetic acid or dilute hydrochloric acid: [1] By reacting bromine with aniline in water, a white precipitate immediately forms and that is 2,4,6-tribromoaniline
Brominating aniline with elemental bromine gives 2,4,6-tribromoaniline. This is then diazotized, then reacted with ethanol to replace the diazonium group with hydrogen, forming 1,3,5-tribromobenzene. [3] It has also been prepared by these methods: [3] replacement of the amino group of 3,5-dibromoaniline with bromine
4-Bromoaniline is a compound where an aniline molecule is substituted with a bromine atom on the para position. Commercially available, this compound may be used as a building block, e.g. in the preparation of monobrominated biphenyl via the Gomberg-Bachmann reaction .
The formation of a brominated phenol (i.e. 2,4,6-tribromophenol) or aniline (i.e. 2,4,6-tribromoaniline) in form of a white precipitate indicates that the unknown was a phenol or aniline. The more unsaturated an unknown is, the more bromine it reacts with, and the less coloured the solution will appear. [1]
The bromoanilines form a group of three isomers where the bromine atom occupies the para, ortho or meta position on the aromatic ring. Bromoaniline isomers Arene substitution patterns. The three isomers are: 2-Bromoaniline (o-Bromoaniline) [1] 3-Bromoaniline (m-Bromoaniline) [2] 4-Bromoaniline (p-Bromoaniline) [3]
At the same time PBr 3 can react as an electrophile or Lewis acid in many of its reactions, for example with amines. An important reaction of PBr 3 is with alcohols, where it replaces an OH group with a bromine atom to produce an alkyl bromide. All three bromides can be transferred. [4] PBr 3 + 3 (CH 3) 2 CHCH 2 OH → 3 (CH 3) 2 CHCH 2 Br + HP ...
This Wikipedia page provides a comprehensive list of boiling and freezing points for various solvents.
Industrially, it is mainly produced by the reaction of hydrogen gas with bromine gas at 200–400 °C with a platinum catalyst. However, reduction of bromine with red phosphorus is a more practical way to produce hydrogen bromide in the laboratory: [2] 2 P + 6 H 2 O + 3 Br 2 → 6 HBr + 2 H 3 PO 3 H 3 PO 3 + H 2 O + Br 2 → 2 HBr + H 3 PO 4