enow.com Web Search

Search results

  1. Results from the WOW.Com Content Network
  2. Semaphore (programming) - Wikipedia

    en.wikipedia.org/wiki/Semaphore_(programming)

    The counting semaphore concept can be extended with the ability to claim or return more than one "unit" from the semaphore, a technique implemented in Unix. The modified V and P operations are as follows, using square brackets to indicate atomic operations , i.e., operations that appear indivisible to other processes:

  3. Dining philosophers problem - Wikipedia

    en.wikipedia.org/wiki/Dining_philosophers_problem

    Illustration of the dining philosophers problem. Each philosopher has a bowl of spaghetti and can reach two of the forks. In computer science, the dining philosophers problem is an example problem often used in concurrent algorithm design to illustrate synchronization issues and techniques for resolving them.

  4. Producer–consumer problem - Wikipedia

    en.wikipedia.org/wiki/Producer–consumer_problem

    The original semaphore bounded buffer solution was written in ALGOL style. The buffer can store N portions or elements. The "number of queueing portions" semaphore counts the filled locations in the buffer, the "number of empty positions" semaphore counts the empty locations in the buffer and the semaphore "buffer manipulation" works as mutex for the buffer put and get operations.

  5. Readers–writer lock - Wikipedia

    en.wikipedia.org/wiki/Readers–writer_lock

    A common use might be to control access to a data structure in memory that cannot be updated atomically and is invalid (and should not be read by another thread) until the update is complete. Readers–writer locks are usually constructed on top of mutexes and condition variables , or on top of semaphores .

  6. Talk:Semaphore (programming) - Wikipedia

    en.wikipedia.org/wiki/Talk:Semaphore_(programming)

    If the semaphore variable is now negative, the process executing wait() is blocked (i.e., added to the semaphore's queue) until the value is greater or equal to 1. Otherwise, the process continues execution, having used a unit of the resource. signal(): Increments the value of semaphore variable by 1.

  7. Sleeping barber problem - Wikipedia

    en.wikipedia.org/wiki/Sleeping_barber_problem

    # The first two are mutexes (only 0 or 1 possible) Semaphore barberReady = 0 Semaphore accessWRSeats = 1 # if 1, the number of seats in the waiting room can be incremented or decremented Semaphore custReady = 0 # the number of customers currently in the waiting room, ready to be served int numberOfFreeWRSeats = N # total number of seats in the ...

  8. Forget salty, sweet, and umami—2025 is the year of sour. More specifically, sour cherries are about to have a moment, according to market research firm Mintel's 2025 Global Food and Drinks ...

  9. Readers–writers problem - Wikipedia

    en.wikipedia.org/wiki/Readers–writers_problem

    The resource semaphore can be locked by both the writer and the reader in their entry section. They are only able to do so after first locking the readtry semaphore, which can only be done by one of them at a time. It will then take control over the resource as soon as the current reader is done reading and lock all future readers out.