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This is equivalent to calculating the Thevenin resistance. When there are dependent sources, the more general method must be used. The voltage at the terminals is calculated for an injection of a 1 ampere test current at the terminals. This voltage divided by the 1 A current is the Norton impedance R no (in ohms). This method must be used if ...
A general formula for the current I X in a resistor R X that is in parallel with a combination of other resistors of total resistance R T (see Figure 1) is [1] = +, where I T is the total current entering the combined network of R X in parallel with R T.
Network analysis is the process of finding the voltages across, and the currents through, all network components. There are many techniques for calculating these values; however, for the most part, the techniques assume linear components. Except where stated, the methods described in this article are applicable only to linear network analysis
The current through the network is equal to the sum of the currents through each component. The two preceding statements are equivalent, except for exchanging the role of voltage and current . A circuit composed solely of components connected in series is known as a series circuit ; likewise, one connected completely in parallel is known as a ...
In power supply design, a bridge circuit or bridge rectifier is an arrangement of diodes or similar devices used to rectify an electric current, i.e. to convert it from an unknown or alternating polarity to a direct current of known polarity. In some motor controllers, an H-bridge is used to control the direction the motor turns.
These include resistors in series, resistors in parallel and the extension to series and parallel circuits for capacitors, inductors and general impedances. Also well known are the Norton and Thévenin equivalent current generator and voltage generator circuits respectively, as is the Y-Δ transform. None of these are discussed in detail here ...
In the example, calculating the equivalent voltage: = + (+) + = + (+) + = = (Notice that R 1 is not taken into consideration, as above calculations are done in an open-circuit condition between A and B, therefore no current flows through this part, which means there is no current through R 1 and therefore no voltage drop along this part.)
Source transformations are easy to compute using Ohm's law.If there is a voltage source in series with an impedance, it is possible to find the value of the equivalent current source in parallel with the impedance by dividing the value of the voltage source by the value of the impedance.