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As with the octal and hexadecimal numeral systems, quaternary has a special relation to the binary numeral system.Each radix four, eight, and sixteen is a power of two, so the conversion to and from binary is implemented by matching each digit with two, three, or four binary digits, or bits.
Balanced ternary is a ternary numeral system (i.e. base 3 with three digits) that uses a balanced signed-digit representation of the integers in which the digits have the values −1, 0, and 1.
A ternary / ˈ t ɜːr n ər i / numeral system (also called base 3 or trinary [1]) has three as its base. Analogous to a bit , a ternary digit is a trit ( tri nary dig it ). One trit is equivalent to log 2 3 (about 1.58496) bits of information .
The Natural Area Code, this is the smallest base such that all of 1 / 2 to 1 / 6 terminate, a number n is a regular number if and only if 1 / n terminates in base 30. 32: Duotrigesimal: Found in the Ngiti language. 33: Use of letters (except I, O, Q) with digits in vehicle registration plates of Hong Kong. 34
In the base −2 representation, a signed number is represented using a number system with base −2. In conventional binary number systems, the base, or radix, is 2; thus the rightmost bit represents 2 0, the next bit represents 2 1, the next bit 2 2, and so on. However, a binary number system with base −2 is also possible.
Another use of the base is to show the silver ratio as its representation in base √ 2 is simply 11 √ 2. In addition, the area of a regular octagon with side length 1 √ 2 is 1100 √ 2, the area of a regular octagon with side length 10 √ 2 is 110000 √ 2, the area of a regular octagon with side length 100 √ 2 is 11000000 √ 2, etc…
The nines' complement of a decimal digit is the number that must be added to it to produce 9; the nines' complement of 3 is 6, the nines' complement of 7 is 2, and so on, see table. To form the nines' complement of a larger number, each digit is replaced by its nines' complement.
The most significant digit (10) is "dropped": 10 1 0 11 <- Digits of 0xA10B ----- 10 Then we multiply the bottom number from the source base (16), the product is placed under the next digit of the source value, and then add: 10 1 0 11 160 ----- 10 161 Repeat until the final addition is performed: 10 1 0 11 160 2576 41216 ----- 10 161 2576 41227 ...